Math Problem Statement

=(2.53/(1+0.11))/(0.15-0.11)

Solution

Let's solve the expression step by step:

Expression=2.531+0.110.150.11\text{Expression} = \frac{\frac{2.53}{1 + 0.11}}{0.15 - 0.11}

First, calculate the denominator of the inner fraction: 1+0.11=1.111 + 0.11 = 1.11

Then, divide 2.53 by 1.11: 2.531.112.279279279\frac{2.53}{1.11} \approx 2.279279279

Now, calculate the denominator of the main fraction: 0.150.11=0.040.15 - 0.11 = 0.04

Finally, divide the result of the inner fraction by 0.04: 2.2792792790.0456.98198198\frac{2.279279279}{0.04} \approx 56.98198198

So, the final result is approximately: 56.98\boxed{56.98}It seems there was an issue with processing the expression. Let me re-calculate it for you.

We have:

Expression=2.531+0.110.150.11\text{Expression} = \frac{\frac{2.53}{1 + 0.11}}{0.15 - 0.11}

  1. Calculate 1+0.11=1.111 + 0.11 = 1.11.
  2. Then, divide 2.532.53 by 1.111.11: 2.531.112.279279279\frac{2.53}{1.11} \approx 2.279279279
  3. Next, calculate 0.150.11=0.040.15 - 0.11 = 0.04.
  4. Finally, divide 2.2792792792.279279279 by 0.040.04: 2.2792792790.0456.98\frac{2.279279279}{0.04} \approx 56.98

So, the final result is approximately 56.98\boxed{56.98}.

Would you like more details, or do you have any questions?

Here are 5 related questions you might find interesting:

  1. How would the result change if the subtraction in the denominator was 0.150.100.15 - 0.10?
  2. What happens to the result if you change the numerator 2.532.53 to 5.065.06?
  3. How would you calculate the expression if 0.110.11 was negative?
  4. What does changing the value in the denominator tell you about the sensitivity of the result?
  5. How does the result compare if the inner fraction's denominator changes to 22 instead of 1+0.111 + 0.11?

Tip: When working with complex fractions, always simplify the expression step by step to avoid errors.