100−50+25−12+6−3+2−1+4−2+3−1+2−0+1−1+0+3−3+1−0+1−2+5−3

Let's solve the expression:

\[
100 - 50 + 25 - 12 + 6 - 3 + 2 - 1 + 4 - 2 + 3 - 1 + 2 - 0 + 1 - 1 + 0 + 3 - 3 + 1 - 0 + 1 - 2 + 5 - 3
\]

We'll proceed step by step:

1. \( 100 - 50 = 50 \)
2. \( 50 + 25 = 75 \)
3. \( 75 - 12 = 63 \)
4. \( 63 + 6 = 69 \)
5. \( 69 - 3 = 66 \)
6. \( 66 + 2 = 68 \)
7. \( 68 - 1 = 67 \)
8. \( 67 + 4 = 71 \)
9. \( 71 - 2 = 69 \)
10. \( 69 + 3 = 72 \)
11. \( 72 - 1 = 71 \)
12. \( 71 + 2 = 73 \)
13. \( 73 - 0 = 73 \)
14. \( 73 + 1 = 74 \)
15. \( 74 - 1 = 73 \)
16. \( 73 + 0 = 73 \)
17. \( 73 + 3 = 76 \)
18. \( 76 - 3 = 73 \)
19. \( 73 + 1 = 74 \)
20. \( 74 - 0 = 74 \)
21. \( 74 + 1 = 75 \)
22. \( 75 - 2 = 73 \)
23. \( 73 + 5 = 78 \)
24. \( 78 - 3 = 75 \)

Thus, the value of the entire expression is:

\[
n = 75
\]

Would you like more details or have any questions?

Here are 5 related questions:
1. How do you simplify a long arithmetic expression with both addition and subtraction?
2. What is the value of \( 200 - 100 + 50 - 25 + 12 - 6 + 3 \)?
3. How can you use parentheses to group operations in a long arithmetic expression?
4. How do you approach solving an expression with multiple operations efficiently?
5. What strategies can you use to check your work in a long sequence of operations?

**Tip**: When solving long arithmetic expressions, it helps to break them into smaller steps to avoid errors and ensure accuracy.

Learn how to solve the arithmetic expression 100 - 50 + 25 - 12 + 6 - 3 + 2 - 1 + 4 - 2 + 3 - 1 + 2 - 0 + 1 - 1 + 0 + 3 - 3 + 1 - 0 + 1 - 2 + 5 - 3 step-by-step with a detailed solution. This problem involves basic arithmetic operations including addition and subtraction, suitable for students in Grades 3-5.

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