Math Problem Statement

Three quarters of a number added to two and a half of that number gives 13. Find the missing number.

Solution

The text in the image reads:

"Three quarters of a number added to two and a half of that number gives 13. Find the missing number."

We can translate this into a mathematical equation. Let's call the unknown number xx.

  • Three quarters of the number is 34x\frac{3}{4}x.
  • Two and a half of the number is 52x\frac{5}{2}x.
  • Together, they sum to 13.

So the equation is:

34x+52x=13\frac{3}{4}x + \frac{5}{2}x = 13

To solve this, let's first find a common denominator for the fractions (the least common denominator between 4 and 2 is 4). Therefore:

34x+104x=13\frac{3}{4}x + \frac{10}{4}x = 13

Now, combine the fractions:

3x+10x4=13\frac{3x + 10x}{4} = 13

Simplify the numerator:

13x4=13\frac{13x}{4} = 13

Now, solve for xx by multiplying both sides by 4:

13x=5213x = 52

Finally, divide both sides by 13:

x=4x = 4

Thus, the missing number is x=4x = 4.

Would you like more details or have any further questions?

Here are five related questions you might want to explore:

  1. How would you solve this equation if the fractions were more complex?
  2. What if the equation involved subtraction instead of addition?
  3. Can you solve a similar problem where three different fractions are involved?
  4. How can we check if the solution is correct?
  5. How would the equation change if the sum were a different number, say 20?

Tip: When solving equations with fractions, finding a common denominator is key to simplifying the problem effectively.

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Math Problem Analysis

Mathematical Concepts

Algebra
Fractions
Equations

Formulas

x = 4
(3/4)x + (5/2)x = 13
Combine like terms
Solve for x

Theorems

Basic algebraic manipulation

Suitable Grade Level

Grades 6-8