Math Problem Statement

Solve the absolute-value inequality. Express the answer using interval notation. 9 − |2x + 5| ≤ 8

Solution

To solve the absolute-value inequality 92x+589 - |2x + 5| \leq 8, follow these steps:

Step 1: Isolate the absolute value expression

First, subtract 9 from both sides of the inequality to isolate the absolute value term:

2x+51- |2x + 5| \leq -1

Step 2: Multiply both sides by -1

When you multiply both sides of an inequality by a negative number, the direction of the inequality sign reverses:

2x+51|2x + 5| \geq 1

Step 3: Break down the absolute value inequality

The expression 2x+51|2x + 5| \geq 1 can be broken into two separate inequalities:

2x+51or2x+512x + 5 \geq 1 \quad \text{or} \quad 2x + 5 \leq -1

Step 4: Solve each inequality

For the first inequality:

2x+512x + 5 \geq 1 Subtract 5 from both sides:

2x42x \geq -4 Divide by 2:

x2x \geq -2

For the second inequality:

2x+512x + 5 \leq -1 Subtract 5 from both sides:

2x62x \leq -6 Divide by 2:

x3x \leq -3

Step 5: Combine the solutions

The solution to the inequality is the union of the two intervals:

x3orx2x \leq -3 \quad \text{or} \quad x \geq -2

Step 6: Write the solution in interval notation

The interval notation for the solution is:

(,3][2,)(-\infty, -3] \cup [-2, \infty)

This is the solution to the inequality.

Would you like more details or have any questions?

Here are 5 related questions to further explore:

  1. How would the solution change if the inequality was 2x+51|2x + 5| \leq 1 instead?
  2. What would be the graphical representation of the solution on a number line?
  3. How do you solve absolute value equations compared to inequalities?
  4. What happens if the absolute value inequality involves a quadratic expression?
  5. Can you explain how to solve inequalities involving two absolute values?

Tip: Always check your solution by substituting values from each interval back into the original inequality.

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Math Problem Analysis

Mathematical Concepts

Absolute Value Inequalities

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12