Math Problem Statement

2−5∣4x−10∣= −43

Solution

We are given the equation:

254x10=432 - 5 |4x - 10| = -43

Step 1: Isolate the absolute value term

First, subtract 2 from both sides to simplify:

54x10=432-5 |4x - 10| = -43 - 2

54x10=45-5 |4x - 10| = -45

Step 2: Eliminate the negative coefficient

Now, divide both sides by -5 to eliminate the negative coefficient:

4x10=455|4x - 10| = \frac{-45}{-5}

4x10=9|4x - 10| = 9

Step 3: Solve for the variable inside the absolute value

The absolute value equation implies two cases:

Case 1: 4x10=94x - 10 = 9

Solve for xx:

4x=9+104x = 9 + 10

4x=194x = 19

x=194x = \frac{19}{4}

Case 2: 4x10=94x - 10 = -9

Solve for xx:

4x=9+104x = -9 + 10

4x=14x = 1

x=14x = \frac{1}{4}

Final Solutions:

The solutions are:

x=194orx=14x = \frac{19}{4} \quad \text{or} \quad x = \frac{1}{4}

Would you like a detailed explanation of any step?


Here are 5 related questions you might find interesting:

  1. How do you solve absolute value inequalities?
  2. What happens when absolute values are inside more complex expressions?
  3. Can absolute value equations have no solution?
  4. How can graphing help visualize solutions to absolute value equations?
  5. How do you handle systems of equations involving absolute values?

Tip: Always check both cases when solving absolute value equations to avoid missing any solutions.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Equations
Linear Equations

Formulas

Absolute Value Equation: |ax + b| = c
Linear Equation Solution: ax + b = c

Theorems

Absolute Value Properties: |x| = a implies two cases: x = a or x = -a

Suitable Grade Level

Grades 8-10