Math Problem Statement

4753 = 9900 * A * B * C * D. Find the sum of A, B, C, and D.

Solution

We are given the equation:

4753=9900×A×B×C×D4753 = 9900 \times A \times B \times C \times D

First, isolate the product A×B×C×DA \times B \times C \times D by dividing both sides by 9900:

A×B×C×D=47539900A \times B \times C \times D = \frac{4753}{9900}

Simplifying the fraction:

A×B×C×D=47539900A \times B \times C \times D = \frac{4753}{9900}

Next, check if 47539900\frac{4753}{9900} can be simplified, but since 4753 is a prime number, the fraction does not simplify further.

At this point, there is not enough information to uniquely determine AA, BB, CC, and DD, since their values are interdependent. However, if you are asked to find the sum A+B+C+DA + B + C + D, you would need further constraints (e.g., specific integer values for AA, BB, CC, or DD).

Would you like to clarify or impose additional conditions to proceed?

Here are 5 related questions:

  1. Are AA, BB, CC, and DD required to be integers?
  2. Could any of the variables be negative?
  3. Is there a constraint on the values of AA, BB, CC, and DD?
  4. Are there any known values for some of the variables?
  5. Should we explore approximate values for AA, BB, CC, and DD?

Tip: Always check if more information or constraints are needed when solving for multiple variables!

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Math Problem Analysis

Mathematical Concepts

Algebra
Multiplication
Prime Numbers
Fractions

Formulas

A * B * C * D = 4753 / 9900

Theorems

Prime Number Theorem (recognition that 4753 is prime)

Suitable Grade Level

Grades 9-11