The expression you provided is:

\[
100 \div 4(2+3)
\]

First, let's solve inside the parentheses:

\[
2 + 3 = 5
\]

Now, the expression becomes:

\[
100 \div 4(5)
\]

Next, we follow the order of operations (PEMDAS/BODMAS). Since division and multiplication have the same priority, we perform them from left to right. First, divide:

\[
100 \div 4 = 25
\]

Then multiply by 5:

\[
25 \times 5 = 125
\]

So, the result is:

\[
\boxed{125}
\]

Would you like further details or have any questions?

Here are 5 related questions to further explore:

1. How would the result change if the operation were written as \( \frac{100}{4(2+3)} \)?
2. Can you explain how parentheses affect the order of operations in this case?
3. What happens if the multiplication operator was explicitly written as \( 100 \div (4 \times (2+3)) \)?
4. How do you handle the division and multiplication when both appear together in an expression?
5. Can you show how to solve this expression using different groupings?

**Tip:** Always simplify expressions inside parentheses first, and follow the order of operations strictly to avoid errors.

Discover how to solve the arithmetic expression 100 ÷ 4(2+3) step by step. This problem involves the use of parentheses and the order of operations (PEMDAS/BODMAS), including division and multiplication. Perfect for students in Grades 6-8 who are learning how to apply arithmetic rules accurately.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation