Math Problem Statement

What are the solutions to a quadratic equation?

Solution

The solutions to a quadratic equation of the form:

ax2+bx+c=0ax^2 + bx + c = 0

are given by the quadratic formula:

x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Explanation:

  1. Discriminant Δ=b24ac\Delta = b^2 - 4ac:

    • If Δ>0\Delta > 0, there are two distinct real solutions.
    • If Δ=0\Delta = 0, there is one real solution (a repeated root).
    • If Δ<0\Delta < 0, there are two complex conjugate solutions.
  2. Factoring (if possible):

    • If the quadratic can be factored as (xr)(xs)=0(x - r)(x - s) = 0, then the solutions are simply x=rx = r and x=sx = s.
  3. Completing the Square:

    • Another method to solve quadratics is by rewriting it in the form (x+d)2=e(x + d)^2 = e and solving for xx.

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Related Questions:

  1. How do you derive the quadratic formula?
  2. How can you determine the nature of roots without solving the equation?
  3. What are real-life applications of quadratic equations?
  4. How do you solve a quadratic equation graphically?
  5. How do you use the quadratic formula for complex numbers?

Tip:

Always check the discriminant first—it tells you what kind of solutions to expect!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Factoring
Completing the Square
Discriminant
Complex Numbers

Formulas

Quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

Theorems

Quadratic formula theorem
Discriminant theorem

Suitable Grade Level

Grades 9-12