Math Problem Statement

Which of the following points is a solution to the equation 3x + 2y = 12? - (2, 3) - (4, 0) - (0, 6) - (-2, 9)

Solution

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Problem Statement: The equation given is:

3x+2y=123x + 2y = 12

You are asked to identify which one of the following points is a solution to this equation:

  • (2, 3)
  • (4, 0)
  • (0, 6)
  • (-2, 9)

Solution:

To determine which point is a solution, substitute the values of xx and yy from each point into the equation 3x+2y=123x + 2y = 12 and check if the equation holds true.

  1. Point (2, 3): 3(2)+2(3)=6+6=12(True)3(2) + 2(3) = 6 + 6 = 12 \quad \text{(True)} This point satisfies the equation.

  2. Point (4, 0): 3(4)+2(0)=12+0=12(True)3(4) + 2(0) = 12 + 0 = 12 \quad \text{(True)} This point also satisfies the equation.

  3. Point (0, 6): 3(0)+2(6)=0+12=12(True)3(0) + 2(6) = 0 + 12 = 12 \quad \text{(True)} This point also satisfies the equation.

  4. Point (-2, 9): 3(2)+2(9)=6+18=12(True)3(-2) + 2(9) = -6 + 18 = 12 \quad \text{(True)} This point also satisfies the equation.

Conclusion:

All the given points (2, 3), (4, 0), (0, 6), and (-2, 9) satisfy the equation 3x+2y=123x + 2y = 12. Therefore, all of these points are solutions to the equation.


Would you like a more detailed explanation or have any further questions?

Here are some related questions you might find helpful:

  1. How do you solve systems of linear equations using substitution or elimination?
  2. What is the graphical representation of a linear equation in two variables?
  3. How can you find the intercepts of a linear equation?
  4. What are the methods to determine if a point lies on a given line?
  5. How can you check solutions for non-linear equations?

Tip: When solving for the solution to an equation, always substitute the values back into the original equation to ensure they satisfy it.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
Coordinate Geometry

Formulas

Linear equation: ax + by = c

Theorems

Substitution method for verifying solutions to equations

Suitable Grade Level

Grades 6-8