Math Problem Statement

Increases in snow levels are recorded with positive numbers. Decreases in snow levels are recorded with negative numbers. After a winter storm, the snow on Cherry Street started melting at a rate of

[\dfrac{1}{3} \text{ cm}] per hour. What was the total change in depth of the snow on Cherry Street after [3] hours?

Solution

The problem states that the snow on Cherry Street is melting, which corresponds to a decrease in snow levels, so we use a negative value for the rate of melting.

The melting rate is:

13 cm per hour.\dfrac{1}{3} \text{ cm per hour}.

To find the total change in the snow depth after 3 hours, we multiply the melting rate by the number of hours:

Total change=(13×3)=1 cm.\text{Total change} = - \left( \dfrac{1}{3} \times 3 \right) = -1 \text{ cm}.

Therefore, the total change in depth of the snow after 3 hours is a decrease of:

1 cm.\boxed{-1 \text{ cm}}.

Would you like a more detailed explanation? Or do you have any other questions?

Here are 5 related questions to deepen your understanding:

  1. What would be the total change if the snow melted for 5 hours at the same rate?
  2. How would the problem change if the snow increased instead of melting?
  3. If the snow melted at a rate of 12 cm per hour\dfrac{1}{2} \text{ cm per hour}, what would be the total change after 3 hours?
  4. What if the snow melted for only 2 hours at the same rate of 13 cm per hour\dfrac{1}{3} \text{ cm per hour}?
  5. If the snow started increasing instead at a rate of 13 cm per hour\dfrac{1}{3} \text{ cm per hour}, what would be the total increase after 3 hours?

Tip: When dealing with negative values in real-world scenarios (such as melting or decreases), always check the context to ensure you assign the correct sign to the change.

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Math Problem Analysis

Mathematical Concepts

Rates of change
Negative numbers
Multiplication

Formulas

Total change = Rate × Time

Theorems

Multiplication of a constant rate over time
Handling negative values for decreases

Suitable Grade Level

Grades 6-8