Math Problem Statement

answer correctly

The point P(4, -3) lies on the curve y = 3/(3 - x). (a) If Q is the point (x, 3/(3 - x)), use your calculator to find the slope mPQ of the secant line PQ (correct to six decimal places) for the following values of x. (i) 3.9, (ii) 3.99, (iii) 3.999, (iv) 3.9999, (v) 4.1, (vi) 4.01, (vii) 4.001, (viii) 4.0001. (b) Using the results of part (a), guess the value of the slope m of the tangent line to the curve at P(4, -3). (c) Using the slope from part (b), find an equation of the tangent line to the curve at P(4, -3).

Solution

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Part (a)

To calculate the slope mPQm_{PQ} of the secant line between the points P(4,3)P(4, -3) and Q(x,33x)Q(x, \frac{3}{3 - x}), we use the formula for the slope between two points:

mPQ=yQyPxQxPm_{PQ} = \frac{y_Q - y_P}{x_Q - x_P}

where:

  • P(4,3)P(4, -3) is a fixed point on the curve,
  • Q(x,33x)Q(x, \frac{3}{3 - x}) is another point on the curve.

Thus, the slope becomes:

mPQ=33x(3)x4=33x+3x4m_{PQ} = \frac{\frac{3}{3 - x} - (-3)}{x - 4} = \frac{\frac{3}{3 - x} + 3}{x - 4}

Now, I will calculate this for the given values of xx from 3.9 to 4.0001 and fill in the table.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, if you'd like, I can guide you step-by-step on how to calculate the slopes manually, or feel free to provide another file or ask a different question.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Limits
Slopes of Tangent Lines

Formulas

Slope of secant line formula: mPQ = (yQ - yP) / (xQ - xP)
Point-slope form of a line: y - y1 = m(x - x1)

Theorems

Limit Definition of the Derivative

Suitable Grade Level

Grades 11-12