Math Problem Statement

Sketch a graph of the function f(x) = x^3 - 2x^2 + 4x + 1 using Key Idea 3.5.1. Show all work and check your answer with technology.

Solution

To sketch the graph of the function f(x)=x32x2+4x+1f(x) = x^3 - 2x^2 + 4x + 1 using Key Idea 3.5.1 (likely related to analyzing critical points, inflection points, and behavior at infinity), let’s go through these steps:

Step 1: Identify the Function and its Derivatives

  1. Given function: f(x)=x32x2+4x+1f(x) = x^3 - 2x^2 + 4x + 1.
  2. First derivative f(x)f'(x): To find critical points (where f(x)=0f'(x) = 0), we’ll take the derivative: f(x)=3x24x+4f'(x) = 3x^2 - 4x + 4
  3. Second derivative f(x)f''(x): To find inflection points, we take the derivative of f(x)f'(x): f(x)=6x4f''(x) = 6x - 4

Step 2: Find Critical Points (Using f(x)=0f'(x) = 0)

Set f(x)=0f'(x) = 0 to find values of xx where the function might have a maximum, minimum, or saddle point. 3x24x+4=03x^2 - 4x + 4 = 0 Using the quadratic formula: x=(4)±(4)243423x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4 \cdot 3 \cdot 4}}{2 \cdot 3} x=4±16486=4±326x = \frac{4 \pm \sqrt{16 - 48}}{6} = \frac{4 \pm \sqrt{-32}}{6} This results in imaginary values, so there are no real critical points where f(x)=0f'(x) = 0. Thus, f(x)f(x) has no local maximum or minimum points.

Step 3: Find Inflection Points (Using f(x)=0f''(x) = 0)

Set f(x)=0f''(x) = 0 to find potential inflection points: 6x4=06x - 4 = 0 x=46=23x = \frac{4}{6} = \frac{2}{3} When x=23x = \frac{2}{3}, there is a potential inflection point.

Step 4: Analyze the End Behavior

Since f(x)=x32x2+4x+1f(x) = x^3 - 2x^2 + 4x + 1 is a cubic function, we know that as xx \to \infty, f(x)f(x) \to \infty, and as xx \to -\infty, f(x)f(x) \to -\infty.

Step 5: Sketch the Graph

  • End behavior: Starts from -\infty as xx \to -\infty and rises to ++\infty as xx \to \infty.
  • Inflection point: At x=23x = \frac{2}{3}, the curve changes concavity.
  • No local maxima or minima because the critical points are complex.

Would you like a detailed sketch or have further questions on any of these steps?


Here are some related questions to further explore this topic:

  1. How do you determine the concavity of a function at a given point?
  2. What is the importance of the first derivative in graphing functions?
  3. How can you verify if a function has a local maximum or minimum using derivatives?
  4. Why does a cubic function exhibit end behavior going to ++\infty and -\infty?
  5. How does an inflection point affect the shape of the graph?

Tip: For sketching, always check inflection points and end behavior to capture the main shape of the curve.

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Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Inflection Points
End Behavior

Formulas

First derivative f'(x) = 3x^2 - 4x + 4
Second derivative f''(x) = 6x - 4

Theorems

First Derivative Test
Second Derivative Test

Suitable Grade Level

Grades 11-12