Math Problem Statement

Exercise7. (a)Sketchthecurvewithpolarequationr=2cosθ (b)FindaCartesianequationforthiscurve.

Solution

(a) Sketch the curve with polar equation r=2cosθr = 2\cos\theta

The polar equation r=2cosθr = 2\cos\theta represents a circle. In polar coordinates, rr is the distance from the origin to a point on the curve, and θ\theta is the angle that the line from the origin to the point makes with the positive xx-axis.

To sketch the curve:

  1. Identify the type of curve: The given equation is of the form r=acosθr = a\cos\theta, which is known to be a circle in polar coordinates.

  2. Determine the radius and center:

    • The maximum value of rr occurs when cosθ=1\cos\theta = 1, giving r=2r = 2.
    • The minimum value of rr occurs when cosθ=1\cos\theta = -1, giving r=2r = -2, which reflects the curve across the origin.
    • The curve is a circle with a radius of 11 centered at (1,0)(1, 0) in Cartesian coordinates.
  3. Plot key points:

    • At θ=0\theta = 0, r=2r = 2.
    • At θ=π2\theta = \frac{\pi}{2}, r=0r = 0.
    • At θ=π\theta = \pi, r=2r = -2, which corresponds to r=2r = 2 and θ=0\theta = 0.
    • At θ=3π2\theta = \frac{3\pi}{2}, r=0r = 0.

The curve is a circle that is symmetric about the xx-axis.

(b) Find a Cartesian equation for this curve

To convert the polar equation r=2cosθr = 2\cos\theta into Cartesian coordinates, use the relationships between polar and Cartesian coordinates: x=rcosθandy=rsinθx = r\cos\theta \quad \text{and} \quad y = r\sin\theta r2=x2+y2r^2 = x^2 + y^2 From the polar equation r=2cosθr = 2\cos\theta, multiply both sides by rr to get: r2=2rcosθr^2 = 2r\cos\theta Substitute r2=x2+y2r^2 = x^2 + y^2 and rcosθ=xr\cos\theta = x into the equation: x2+y2=2xx^2 + y^2 = 2x Rearrange the equation: x22x+y2=0x^2 - 2x + y^2 = 0 Complete the square for xx: (x1)21+y2=0(x - 1)^2 - 1 + y^2 = 0 (x1)2+y2=1(x - 1)^2 + y^2 = 1 This is the equation of a circle with a radius of 11 centered at (1,0)(1, 0) in Cartesian coordinates.


Do you want more details or have any questions?

Here are five related questions to explore further:

  1. How would you sketch the polar curve for r=2sinθr = 2\sin\theta?
  2. What is the Cartesian equation for the polar curve r=3cosθr = 3\cos\theta?
  3. How can you derive the equation of an ellipse from a given polar equation?
  4. What is the significance of completing the square when converting from polar to Cartesian coordinates?
  5. How does the graph of r=2cosθr = 2\cos\theta change if we replace the 2 with another constant?

Tip: When converting from polar to Cartesian coordinates, remember to use the identities x=rcosθx = r\cos\theta and y=rsinθy = r\sin\theta to simplify the process.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Cartesian Coordinates
Circle

Formulas

Polar to Cartesian Conversion: x = r * cos(theta), y = r * sin(theta)
Circle Equation: (x - h)^2 + (y - k)^2 = r^2

Theorems

-

Suitable Grade Level

College Level