Math Problem Statement

What is the equation of the sinusoidal graph with an amplitude of 5, a period of 2π, and no vertical or phase shift?

Solution

The graph you uploaded shows a periodic function, likely a sine or cosine wave. Here's a detailed analysis based on the image:

  • Amplitude: The graph reaches a maximum height of 5 and a minimum of -5, so the amplitude is 55.
  • Period: The graph completes a full cycle between π-\pi and 2π2\pi, so the period of the function is 2π2\pi. This suggests no horizontal stretching.
  • Vertical Shift: The midline is along the x-axis, indicating no vertical shift.
  • Phase Shift: The graph does not appear to be horizontally shifted since it crosses the origin, matching the shape of a standard sine function.
  • Equation: Based on the amplitude and the lack of any shift, the equation of this graph is likely: y=5sin(x)y = 5 \sin(x)

It could also represent a cosine function, y=5cos(x)y = 5 \cos(x), with an appropriate phase shift.

Would you like more details or clarification?

Here are 5 related questions for practice:

  1. How would the equation change if the amplitude were doubled?
  2. What would happen to the graph if the period was halved?
  3. How can you determine the function’s frequency from its period?
  4. How does a vertical shift affect the equation of a sine or cosine wave?
  5. What would a phase shift of π4\frac{\pi}{4} look like on this graph?

Tip: When analyzing sine or cosine graphs, remember that the amplitude affects the height, while the period controls the width of the cycles.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Sine and Cosine Functions
Periodic Functions

Formulas

y = A*sin(Bx + C) + D
y = A*cos(Bx + C) + D

Theorems

Properties of Sinusoidal Functions
Amplitude and Period Modifications

Suitable Grade Level

Grades 9-12