Math Problem Statement

In order to approximate the integral using Simpson's rule with an error of magnitude less than 10−8,10−8, what is the smallest number of subintervals needed, according to the error estimate formula?

nn must be at least integral is 8/(s-2)^2 from 3 to 9

Solution

To approximate the integral 398(s2)2ds\int_3^9 \frac{8}{(s-2)^2} \, ds using Simpson's rule with an error less than 10810^{-8}, we calculate the smallest number of subintervals nn required based on Simpson's error estimate formula.

Error estimate formula for Simpson's rule:

ES=(ba)5180n4maxf(4)(x),E_S = \frac{(b-a)^5}{180 n^4} \max |f^{(4)}(x)|, where:

  • [a,b][a, b] is the interval of integration (a=3,b=9a = 3, b = 9),
  • nn is the number of subintervals (must be even),
  • f(x)f(x) is the integrand (f(x)=8(x2)2f(x) = \frac{8}{(x-2)^2}),
  • f(4)(x)f^{(4)}(x) is the fourth derivative of f(x)f(x).

Step 1: Find the fourth derivative f(4)(x)f^{(4)}(x):

The function is: f(x)=8(x2)2.f(x) = \frac{8}{(x-2)^2}.

First derivative: f(x)=16(x2)3.f'(x) = -\frac{16}{(x-2)^3}.

Second derivative: f(x)=48(x2)4.f''(x) = \frac{48}{(x-2)^4}.

Third derivative: f(3)(x)=192(x2)5.f^{(3)}(x) = -\frac{192}{(x-2)^5}.

Fourth derivative: f(4)(x)=960(x2)6.f^{(4)}(x) = \frac{960}{(x-2)^6}.

Step 2: Determine the maximum of f(4)(x)|f^{(4)}(x)| on [3,9][3, 9]:

On the interval [3,9][3, 9], f(4)(x)f^{(4)}(x) is largest when xx is smallest (as (x2)6(x-2)^6 is smallest). At x=3x = 3: f(4)(3)=960(32)6=960.f^{(4)}(3) = \frac{960}{(3-2)^6} = 960.

Thus, maxf(4)(x)=960\max |f^{(4)}(x)| = 960.

Step 3: Apply the error formula and solve for nn:

The error formula becomes: ES(93)5180n4960.E_S \leq \frac{(9-3)^5}{180 n^4} \cdot 960.

Simplify: ES65960180n4.E_S \leq \frac{6^5 \cdot 960}{180 n^4}.

Calculate 65=77766^5 = 7776: ES7776960180n4.E_S \leq \frac{7776 \cdot 960}{180 n^4}.

Simplify the constant: ES7464960180n4=41472n4.E_S \leq \frac{7464960}{180 n^4} = \frac{41472}{n^4}.

Set ES<108E_S < 10^{-8}: 41472n4<108.\frac{41472}{n^4} < 10^{-8}.

Multiply through by n4n^4: 41472<108n4.41472 < 10^{-8} n^4.

Divide through by 10810^{-8}: n4>41472108=4.1472×1012.n^4 > \frac{41472}{10^{-8}} = 4.1472 \times 10^{12}.

Take the fourth root: n>(4.1472×1012)1/4.n > (4.1472 \times 10^{12})^{1/4}.

Step 4: Approximate nn:

(4.1472×1012)1/43165.5.(4.1472 \times 10^{12})^{1/4} \approx 3165.5.

Since nn must be even, the smallest nn is: n=3166.n = 3166.

Final Answer:

The smallest number of subintervals nn is 3166\boxed{3166}.

Would you like a detailed explanation of any step, or do you have any further questions?


Questions to Explore Further:

  1. What is the reasoning behind choosing an even number of subintervals in Simpson's Rule?
  2. How does the fourth derivative affect the error in Simpson's Rule?
  3. What would the error estimate be if we used a smaller nn?
  4. Can you verify the result by numerically integrating 8(s2)2\frac{8}{(s-2)^2} with n=3166n = 3166?
  5. How does Simpson's Rule compare to other numerical methods like the trapezoidal rule for this integral?

Tip:

When approximating integrals with Simpson's Rule, always ensure the integrand is sufficiently smooth (continuous derivatives) over the interval for the method to be effective.

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Math Problem Analysis

Mathematical Concepts

Numerical Integration
Simpson's Rule
Error Analysis in Numerical Methods
Derivatives

Formulas

Simpson's Rule Error Estimate Formula: E_S = (b - a)^5 / (180 n^4) * max |f^(4)(x)|
f^(4)(x) = 960 / (x - 2)^6

Theorems

Error estimate theorem for Simpson's rule

Suitable Grade Level

Grades 11-12 (College-level)