The given expression is:

\[
\frac{(x^2 + 6x + 9)}{(x + 3)}
\]

Now, let's simplify it:

1. First, factor the numerator:

\[
x^2 + 6x + 9 = (x + 3)(x + 3) = (x + 3)^2
\]

2. Now, rewrite the expression:

\[
\frac{(x + 3)^2}{(x + 3)}
\]

3. Since \(x + 3\) is common in both the numerator and denominator, cancel out one factor of \(x + 3\):

\[
(x + 3)
\]

So, the simplified expression is:

\[
x + 3
\]

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:
1. How do you factor quadratic expressions like \(x^2 + 6x + 9\)?
2. Can all quadratics be factored in a similar manner?
3. What happens if \(x = -3\) in the original expression?
4. How do you handle rational expressions with more complex numerators and denominators?
5. What if the denominator had an additional factor?

**Tip:** Always check for factors in the numerator and denominator before simplifying expressions.

This page explains how to simplify the expression (x²+6x+9)÷(x+3) by factoring the quadratic trinomial and canceling common terms. Learn key algebraic techniques for factoring and simplifying rational expressions, perfect for students in Grades 8-10.

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