The expression you're working with is:

$\sec(\theta) \cdot \cot(\theta) \cdot \sin(\theta)$

To simplify this, let's break down the trigonometric functions:

• $\sec(\theta) = \frac{1}{\cos(\theta)}$
• $\cot(\theta) = \frac{\cos(\theta)}{\sin(\theta)}$
• $\sin(\theta)$ stays as is.

Now substitute these into the expression:

$\sec(\theta) \cdot \cot(\theta) \cdot \sin(\theta) = \left(\frac{1}{\cos(\theta)}\right) \cdot \left(\frac{\cos(\theta)}{\sin(\theta)}\right) \cdot \sin(\theta)$

Simplifying step by step:

1. Multiply the first two terms:
   $\frac{1}{\cos(\theta)} \cdot \frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}$

2. Now, multiply by $\sin(\theta)$:
   $\frac{1}{\sin(\theta)} \cdot \sin(\theta) = 1$

So, the simplified result is:

$\sec(\theta) \cdot \cot(\theta) \cdot \sin(\theta) = 1$

Let me know if you'd like more details or further steps!

Here are 5 related questions:

1. What is the value of $\sec(\theta)$ in terms of $\sin(\theta)$?
2. How do you simplify an expression involving multiple trigonometric functions like $\sin$, $\cos$, and $\tan$?
3. How can you prove the identity $\sec(\theta) \cdot \cot(\theta) \cdot \sin(\theta) = 1$ from first principles?
4. How do the trigonometric functions relate to each other on the unit circle?
5. What other trigonometric identities can you use to simplify more complex expressions?

Tip: Always remember to look for opportunities to cancel terms or apply known trigonometric identities when simplifying complex expressions.