Math Problem Statement

Root -18 × root -3

Solution

The expression involves multiplying square roots of negative numbers, which results in complex numbers. Let's break it down:

18×3\sqrt{-18} \times \sqrt{-3}

We can rewrite each square root of a negative number in terms of the imaginary unit ii (where i=1i = \sqrt{-1}):

18=18iand3=3i\sqrt{-18} = \sqrt{18} \cdot i \quad \text{and} \quad \sqrt{-3} = \sqrt{3} \cdot i

Now, multiplying these:

(18i)×(3i)=18×3×i2(\sqrt{18} \cdot i) \times (\sqrt{3} \cdot i) = \sqrt{18} \times \sqrt{3} \times i^2

Since i2=1i^2 = -1:

18×3×(1)=18×3=54\sqrt{18} \times \sqrt{3} \times (-1) = -\sqrt{18 \times 3} = -\sqrt{54}

Now, simplify 54\sqrt{54}:

54=9×6=36\sqrt{54} = \sqrt{9 \times 6} = 3\sqrt{6}

Thus, the final result is:

54=36-\sqrt{54} = -3\sqrt{6}

Final Answer:

18×3=36\sqrt{-18} \times \sqrt{-3} = -3\sqrt{6}

Would you like more details or have any questions?

Here are 5 related questions:

  1. How do you simplify complex numbers involving square roots?
  2. What is the imaginary unit ii and how is it used in math?
  3. How do you simplify the square root of a product like 54\sqrt{54}?
  4. What are the properties of imaginary numbers in multiplication?
  5. How do you simplify expressions involving i2i^2?

Tip: When dealing with square roots of negative numbers, always remember to express them in terms of the imaginary unit ii.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Square Roots
Imaginary Unit

Formulas

√(-a) = √(a) * i, where i = √(-1)
Multiplication of square roots: √a * √b = √(a*b)
i^2 = -1

Theorems

Properties of Imaginary Numbers
Square Root Multiplication Property

Suitable Grade Level

Grades 9-12