Math Problem Statement

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Solve the following rational expressions: (1) (4n-4)/14, (2) (15x^2 + 30x)/(5x + 10), (3) (4x + 12)/(x^2 + 8x + 15), (4) (x^2 - 9)/(x^2 + 5x + 6), (5) (x^2 - 25)/(4x + 20), (6) (x^2 - 9)/(3 - x).

Solution

Let's go step by step and solve each of the rational expressions in the image.

1. 4n414\frac{4n - 4}{14}

Solution: Factor out the common term in the numerator: 4n414=4(n1)14\frac{4n - 4}{14} = \frac{4(n - 1)}{14} Now simplify by dividing both the numerator and denominator by 2: 4(n1)14=2(n1)7\frac{4(n - 1)}{14} = \frac{2(n - 1)}{7} So, the simplified expression is: 2(n1)7\frac{2(n - 1)}{7}

2. 15x2+30x5x+10\frac{15x^2 + 30x}{5x + 10}

Solution: Factor out the greatest common factor (GCF) in both the numerator and denominator: 15x2+30x5x+10=15x(x+2)5(x+2)\frac{15x^2 + 30x}{5x + 10} = \frac{15x(x + 2)}{5(x + 2)} Cancel out the common factor (x+2)(x + 2): 15x(x+2)5(x+2)=15x5=3x\frac{15x(x + 2)}{5(x + 2)} = \frac{15x}{5} = 3x So, the simplified expression is: 3x3x

3. 4x+12x2+8x+15\frac{4x + 12}{x^2 + 8x + 15}

Solution: Factor both the numerator and the denominator:

  • Numerator: 4x+12=4(x+3)4x + 12 = 4(x + 3)
  • Denominator: x2+8x+15=(x+3)(x+5)x^2 + 8x + 15 = (x + 3)(x + 5)

Now cancel out the common factor (x+3)(x + 3): 4(x+3)(x+3)(x+5)=4x+5\frac{4(x + 3)}{(x + 3)(x + 5)} = \frac{4}{x + 5} So, the simplified expression is: 4x+5\frac{4}{x + 5}

4. x29x2+5x+6\frac{x^2 - 9}{x^2 + 5x + 6}

Solution: Factor both the numerator and the denominator:

  • Numerator: x29=(x3)(x+3)x^2 - 9 = (x - 3)(x + 3) (difference of squares)
  • Denominator: x2+5x+6=(x+2)(x+3)x^2 + 5x + 6 = (x + 2)(x + 3)

Now cancel out the common factor (x+3)(x + 3): (x3)(x+3)(x+2)(x+3)=x3x+2\frac{(x - 3)(x + 3)}{(x + 2)(x + 3)} = \frac{x - 3}{x + 2} So, the simplified expression is: x3x+2\frac{x - 3}{x + 2}

5. x2254x+20\frac{x^2 - 25}{4x + 20}

Solution: Factor both the numerator and the denominator:

  • Numerator: x225=(x5)(x+5)x^2 - 25 = (x - 5)(x + 5) (difference of squares)
  • Denominator: 4x+20=4(x+5)4x + 20 = 4(x + 5)

Now cancel out the common factor (x+5)(x + 5): (x5)(x+5)4(x+5)=x54\frac{(x - 5)(x + 5)}{4(x + 5)} = \frac{x - 5}{4} So, the simplified expression is: x54\frac{x - 5}{4}

6. x293x\frac{x^2 - 9}{3 - x}

Solution: Factor the numerator:

  • Numerator: x29=(x3)(x+3)x^2 - 9 = (x - 3)(x + 3) (difference of squares)

Notice that the denominator 3x3 - x can be rewritten as (x3)-(x - 3), since: 3x=(x3)3 - x = -(x - 3) So, the expression becomes: (x3)(x+3)(x3)=(x+3)1=(x+3)\frac{(x - 3)(x + 3)}{-(x - 3)} = \frac{-(x + 3)}{1} = -(x + 3) Thus, the simplified expression is: (x+3)-(x + 3)


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Math Problem Analysis

Mathematical Concepts

Simplification of Rational Expressions
Factoring
Algebraic Fractions
Canceling Common Factors

Formulas

Difference of Squares: a^2 - b^2 = (a - b)(a + b)
Factoring Common Terms

Theorems

Fundamental Theorem of Algebra (for factoring)
Properties of Rational Expressions

Suitable Grade Level

Grades 9-10