Math Problem Statement

use kfc and then factoring then cancelling

Simplify: \frac{(x + 3)(x - 3)}{(x - 4)(x + 5)} \cdot \frac{(x - 4)(x - 4)}{3(x + 3)}

Solution

Let's simplify the given expression step by step. The expression is:

(x+3)(x3)(x4)(x+5)(x4)(x4)3(x+3)\frac{(x + 3)(x - 3)}{(x - 4)(x + 5)} \cdot \frac{(x - 4)(x - 4)}{3(x + 3)}

Step 1: Combine the fractions using multiplication.

We multiply the numerators and denominators:

=(x+3)(x3)(x4)(x4)(x4)(x+5)3(x+3)= \frac{(x + 3)(x - 3) \cdot (x - 4)(x - 4)}{(x - 4)(x + 5) \cdot 3(x + 3)}

Step 2: Cancel common factors.

  • In the numerator and denominator, we have a common factor of (x+3)(x + 3) and (x4)(x - 4).
  • Cancel these common factors:

=(x3)(x4)3(x+5)= \frac{(x - 3) \cdot (x - 4)}{3(x + 5)}

Step 3: Simplify the remaining expression.

Now, we can simplify the numerator:

(x3)(x4)=x24x3x+12=x27x+12(x - 3)(x - 4) = x^2 - 4x - 3x + 12 = x^2 - 7x + 12

So, the expression becomes:

x27x+123(x+5)\frac{x^2 - 7x + 12}{3(x + 5)}

Final Simplified Expression:

x27x+123(x+5)\frac{x^2 - 7x + 12}{3(x + 5)}

This is the simplified form of the given expression.

Would you like more details, or do you have any questions?

Here are 5 related questions to expand this concept:

  1. How do you perform long division on polynomials?
  2. What are the different methods of factoring polynomials?
  3. How do you simplify more complex rational expressions?
  4. What is the difference between factoring and expanding expressions?
  5. How does factoring help in solving quadratic equations?

Tip: Always look for common factors between the numerator and denominator to simplify rational expressions quickly.

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Expressions
Factoring
Simplifying Rational Expressions

Formulas

Difference of squares: (a + b)(a - b) = a^2 - b^2
Factoring Quadratics

Theorems

Cancellation of common factors in rational expressions

Suitable Grade Level

Grades 9-10