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The image asks to simplify the following expression:

\[
(2x + 5)(2x - 5)(3y + 5x)
\]

We can simplify it step by step:

### Step 1: Use the difference of squares formula
The first two terms, \((2x + 5)(2x - 5)\), follow the difference of squares pattern, which is:
\[
(a + b)(a - b) = a^2 - b^2
\]
Here, \(a = 2x\) and \(b = 5\), so we apply this:

\[
(2x + 5)(2x - 5) = (2x)^2 - 5^2 = 4x^2 - 25
\]

### Step 2: Multiply by the remaining term
Now we need to multiply the result \(4x^2 - 25\) by \((3y + 5x)\):

\[
(4x^2 - 25)(3y + 5x)
\]

Distribute each term of \((4x^2 - 25)\) over \((3y + 5x)\):

\[
= 4x^2(3y + 5x) - 25(3y + 5x)
\]

### Step 3: Distribute each term
1. Distribute \(4x^2\) to both \(3y\) and \(5x\):

\[
4x^2(3y + 5x) = 12x^2y + 20x^3
\]

2. Distribute \(-25\) to both \(3y\) and \(5x\):

\[
-25(3y + 5x) = -75y - 125x
\]

### Step 4: Combine all terms
Now, putting it all together:

\[
12x^2y + 20x^3 - 75y - 125x
\]

So, the simplified expression is:

\[
12x^2y + 20x^3 - 75y - 125x
\]

Let me know if you want further details or have any questions!

Here are 5 related questions for practice:
1. How would you multiply two binomials that don’t follow the difference of squares pattern?
2. What is the distributive property and how does it apply to polynomial multiplication?
3. Can you expand and simplify \((x + 3)(x - 2)(x + 5)\)?
4. How can you factor the expression \(4x^2 - 25\) back into binomials?
5. What happens when you multiply polynomials that include more than two variables?

**Tip:** Always look for patterns like difference of squares or common terms to simplify multiplication!

Multiply the following: (2x + 5)(2x - 5)(3y + 5x)

Simplify the polynomial multiplication (2x + 5)(2x - 5)(3y + 5x) using the difference of squares and distributive property. Learn step-by-step how to approach polynomial multiplication in this algebra problem suitable for Grades 9-12.

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