Math Problem Statement

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Solution

The given logarithmic expression is:

log(x7y10)\log\left(\sqrt{x^7 y^{-10}}\right)

Step 1: Rewrite the square root

The square root can be expressed as an exponent of 12\frac{1}{2}:

x7y10=(x7y10)12\sqrt{x^7 y^{-10}} = (x^7 y^{-10})^{\frac{1}{2}}

Step 2: Apply the power rule

Using the logarithmic power rule log(ab)=blog(a)\log(a^b) = b\log(a), we get:

log((x7y10)12)=12log(x7y10)\log\left((x^7 y^{-10})^{\frac{1}{2}}\right) = \frac{1}{2} \log(x^7 y^{-10})

Step 3: Apply the product rule

Using the logarithmic property log(ab)=log(a)+log(b)\log(ab) = \log(a) + \log(b):

12[log(x7)+log(y10)]\frac{1}{2} \left[ \log(x^7) + \log(y^{-10}) \right]

Step 4: Apply the power rule separately

log(x7)=7log(x),log(y10)=10log(y)\log(x^7) = 7\log(x), \quad \log(y^{-10}) = -10\log(y)

Thus, the expression simplifies to:

12(7log(x)10log(y))\frac{1}{2} \left( 7\log(x) - 10\log(y) \right)

Final Answer:

72log(x)5log(y)\frac{7}{2} \log(x) - 5\log(y)


Would you like more details or have any questions?

Here are some related questions to explore:

  1. What are the properties of logarithms used in simplifying expressions?
  2. How do logarithms help in solving exponential equations?
  3. Can logarithms handle negative or zero values inside the argument?
  4. How do you convert logarithmic expressions to exponential form?
  5. What are the different bases of logarithms and their applications?

Tip: When simplifying logarithmic expressions, always check for opportunities to apply power, product, and quotient rules for simplification.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponentiation
Algebra

Formulas

log(a^b) = b * log(a)
log(ab) = log(a) + log(b)

Theorems

Power Rule of Logarithms
Product Rule of Logarithms

Suitable Grade Level

Grades 9-12