Math Problem Statement

Log400+log20-log8+log100

Solution

We can simplify the expression using logarithmic properties. The relevant properties are:

  1. Logarithm of a product: loga(x)+loga(y)=loga(xy)\log_a(x) + \log_a(y) = \log_a(xy)
  2. Logarithm of a quotient: loga(x)loga(y)=loga(xy)\log_a(x) - \log_a(y) = \log_a\left(\frac{x}{y}\right)

The given expression is:

log(400)+log(20)log(8)+log(100)\log(400) + \log(20) - \log(8) + \log(100)

Step 1: Combine the logarithms

First, combine the logarithms based on the properties:

log(400×20×1008)\log\left(\frac{400 \times 20 \times 100}{8}\right)

Step 2: Simplify the inside expression

Now, calculate the value inside the logarithm:

400×20×1008=8000008=100000\frac{400 \times 20 \times 100}{8} = \frac{800000}{8} = 100000

Step 3: Apply the logarithm

Finally, apply the logarithm:

log(100000)\log(100000)

Since log(105)=5\log(10^5) = 5, we get:

log(100000)=5\log(100000) = 5

Thus, the simplified value of the expression is 5.

Would you like more details, or have any questions?


Here are 5 related questions to extend your understanding:

  1. How do logarithmic properties help in simplifying expressions?
  2. Can you simplify log(50)+log(2)log(10)\log(50) + \log(2) - \log(10)?
  3. What happens if we change the base of the logarithms, say to base 2?
  4. How do we deal with logarithmic expressions involving square roots, like log(50)\log(\sqrt{50})?
  5. What is the value of log(xy)\log(xy) in terms of log(x)\log(x) and log(y)\log(y)?

Tip: Remember that logarithms convert multiplication into addition and division into subtraction, making them useful for simplifying complex products and quotients.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Logarithms
Properties of Logarithms
Simplification of Logarithmic Expressions

Formulas

Logarithm of a product: log_a(x) + log_a(y) = log_a(xy)
Logarithm of a quotient: log_a(x) - log_a(y) = log_a(x/y)

Theorems

Logarithmic Properties

Suitable Grade Level

Grades 10-12