The image contains a question with the function $f(x) = \frac{2}{x}$ and asks to find and simplify the following:

(a) $f\left(\frac{a}{4}\right)$

To solve: $f\left(\frac{a}{4}\right) = \frac{2}{\frac{a}{4}} = \frac{2 \cdot 4}{a} = \frac{8}{a}$

(b) $f\left(\frac{22}{a}\right)$

To solve: $f\left(\frac{22}{a}\right) = \frac{2}{\frac{22}{a}} = \frac{2 \cdot a}{22} = \frac{2a}{22} = \frac{a}{11}$

(c) $\frac{f(3+h) - f(3)}{h}$

First, find $f(3+h)$ and $f(3)$: $f(3+h) = \frac{2}{3+h}, \quad f(3) = \frac{2}{3}$ Now compute: $\frac{f(3+h) - f(3)}{h} = \frac{\frac{2}{3+h} - \frac{2}{3}}{h}$ Simplifying the numerator: $\frac{2}{3+h} - \frac{2}{3} = \frac{2(3) - 2(3+h)}{(3+h)(3)} = \frac{6 - (6 + 2h)}{(3+h)(3)} = \frac{-2h}{(3+h)(3)}$ Now substitute this into the original expression: $\frac{\frac{-2h}{(3+h)(3)}}{h} = \frac{-2}{(3+h)(3)}$

Let me know if you'd like any more details or have any questions! Here are five related questions:

1. What is the general process for simplifying complex fractions?
2. How does one compute the difference quotient $\frac{f(x+h) - f(x)}{h}$ for a given function?
3. How do you determine the domain of $f(x) = \frac{2}{x}$?
4. What does the difference quotient represent in calculus?
5. How does the result of part (c) relate to the derivative of the function?

Tip: When simplifying expressions involving fractions, always try to find a common denominator to combine terms effectively!