Math Problem Statement

𝑥/2+𝑥/3+𝑥/4

Solution

The expression you provided is:

x2+x3+x4\frac{x}{2} + \frac{x}{3} + \frac{x}{4}

To simplify this, let's first find the least common denominator (LCD) of 2, 3, and 4. The LCD of these numbers is 12.

Now, let's rewrite each fraction with the denominator of 12:

x2=6x12,x3=4x12,x4=3x12\frac{x}{2} = \frac{6x}{12}, \quad \frac{x}{3} = \frac{4x}{12}, \quad \frac{x}{4} = \frac{3x}{12}

Now, add the fractions:

6x12+4x12+3x12=6x+4x+3x12=13x12\frac{6x}{12} + \frac{4x}{12} + \frac{3x}{12} = \frac{6x + 4x + 3x}{12} = \frac{13x}{12}

Thus, the simplified expression is:

13x12\frac{13x}{12}

Would you like more details on how this was solved or on any related concepts?

Here are 5 questions related to this:

  1. What is the least common denominator, and why is it important in adding fractions?
  2. How would the result change if the numerators had different values?
  3. Can you apply this method to expressions with more complex denominators?
  4. How does this approach work when adding algebraic fractions with variables in the denominator?
  5. How do you handle equations that involve both addition and multiplication of fractions?

Tip: When simplifying fractions, always look for the least common denominator to combine them efficiently.

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Math Problem Analysis

Mathematical Concepts

Algebra
Fractions
Least Common Denominator

Formulas

\frac{x}{a} + \frac{x}{b} + \frac{x}{c} = \frac{a'x + b'x + c'x}{LCD(a,b,c)}

Theorems

Least Common Denominator

Suitable Grade Level

Grades 6-8