The expression \( \frac{6}{6} + \frac{8}{8} \) simplifies as follows:

\[
\frac{6}{6} = 1 \quad \text{and} \quad \frac{8}{8} = 1
\]

So:

\[
1 + 1 = 2
\]

Thus, \( \frac{6}{6} + \frac{8}{8} = 2 \).

Would you like more details or have any other questions?

Here are 5 related questions:
1. What is \( \frac{5}{5} + \frac{10}{10} \)?
2. How do you simplify \( \frac{7}{7} + \frac{3}{3} \)?
3. What is the general rule for simplifying fractions where the numerator equals the denominator?
4. How does this apply to improper fractions like \( \frac{12}{12} \)?
5. Can you add fractions with different denominators in the same way?

**Tip:** When the numerator and denominator are the same in a fraction, the fraction always equals 1!

Explore how to simplify the expression 6/6 + 8/8 with step-by-step guidance. This problem demonstrates basic arithmetic concepts, including fraction simplification, making it suitable for students in Grades 3-5.

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