I can see the image, and the two problems are as follows:

Problem 11: $\left(\frac{3x}{y^5}\right)^{-5}$ You need to rewrite this using only positive exponents and simplify.

Problem 12: $\frac{8y^{-1}z^{-5}}{16yz^{-5}}$ Again, this needs to be rewritten using positive exponents and simplified.

I'll solve both problems step by step.

Problem 11 Solution:

We start by applying the negative exponent to both the numerator and the denominator of the fraction: $\left(\frac{3x}{y^5}\right)^{-5} = \frac{(y^5)^5}{(3x)^5} = \frac{y^{25}}{3^5 \cdot x^5} = \frac{y^{25}}{243x^5}$

Problem 12 Solution:

We simplify by combining like terms and eliminating negative exponents: $\frac{8y^{-1}z^{-5}}{16yz^{-5}} = \frac{8}{16} \cdot \frac{y^{-1}}{y} \cdot \frac{z^{-5}}{z^{-5}} = \frac{1}{2} \cdot \frac{1}{y^2} \cdot 1 = \frac{1}{2y^2}$

Let me know if you need more clarification on these steps or further details!

Here are 5 related questions to deepen your understanding:

1. How do you simplify expressions with negative exponents?
2. What happens when you multiply two powers with the same base?
3. How would you simplify $\left(\frac{a}{b^2}\right)^{-3}$?
4. What is the general rule for raising a fraction to a negative exponent?
5. How does changing the sign of an exponent affect the reciprocal of a fraction?

Tip: Always remember to convert negative exponents into positive ones by using reciprocals.