The expression in the image you uploaded is:

$\left( \frac{-3a^2}{b^{-3}} \right)^2$

To simplify this expression, follow these steps:

1. Apply the exponent to both the numerator and denominator: $\left( \frac{-3a^2}{b^{-3}} \right)^2 = \frac{(-3a^2)^2}{(b^{-3})^2}$
2. Simplify the powers: $(-3a^2)^2 = (-3)^2 \cdot (a^2)^2 = 9a^4$ $(b^{-3})^2 = b^{-6}$
3. Now the expression becomes: $\frac{9a^4}{b^{-6}}$
4. Simplify the negative exponent in the denominator: $\frac{9a^4}{b^{-6}} = 9a^4 \cdot b^6$ So, the simplified form of the expression is: $9a^4b^6$

Let me know if you'd like further clarification or if you have any more questions!

Here are 5 related questions you might find interesting:

1. How do you handle exponents with negative values in algebra?
2. Can you explain how to simplify a fraction with negative exponents?
3. What are the rules for multiplying terms with exponents?
4. How does exponentiation interact with division in algebraic expressions?
5. Can you expand a binomial expression raised to a power?

Tip: Remember that negative exponents mean you take the reciprocal of the base raised to the positive exponent!