The expression provided in the image is as follows:

$\frac{\left(2 \times 10^2 \, \text{g} + 8.123 \, \text{g}\right)}{(0.091 \, \text{cm}^3 - 0.079 \, \text{cm}^3)} - \square \times \frac{5}{7} \, \text{cm}$

To solve this expression step-by-step, we can proceed as follows:

Step 1: Simplify the numerator

The numerator is: $2 \times 10^2 \, \text{g} + 8.123 \, \text{g}$

$2 \times 10^2 = 200 \, \text{g}$ So: $200 \, \text{g} + 8.123 \, \text{g} = 208.123 \, \text{g}$

Step 2: Simplify the denominator

The denominator is: $0.091 \, \text{cm}^3 - 0.079 \, \text{cm}^3$ $0.091 \, \text{cm}^3 - 0.079 \, \text{cm}^3 = 0.012 \, \text{cm}^3$

Step 3: Divide the numerator by the denominator

$\frac{208.123 \, \text{g}}{0.012 \, \text{cm}^3} = 17343.5833 \, \text{g/cm}^3$

Step 4: Subtract the expression on the right

The expression now is: $17343.5833 - \square \times \frac{5}{7} \, \text{cm}$

Since the square is a placeholder, you need to determine the value or leave it as is. Therefore, the expression can be simplified as:

$17343.5833 - \square \times \frac{5}{7} \, \text{cm}$

Would you like to proceed with more details on this calculation, or do you have any other questions?

Related Questions:

1. What happens if the value in the square is zero?
2. How do unit conversions impact the final expression?
3. How can this expression be applied to real-world physics problems?
4. What if the numerator was a different number?
5. How would this expression change if the denominator values were negative?

Tip:

Always ensure units are consistent throughout the calculation to avoid errors, especially when dealing with physical quantities like mass, volume, and length.