Math Problem Statement

Fully simplify the following expression: (7a^9b^(-5))^2. Give your answer without any negative indices.

Solution

The expression you need to simplify is:

(7a9b5)2\left( 7a^9b^{-5} \right)^2

Step-by-Step Solution:

  1. Apply the exponent to each factor: When raising a product to an exponent, we distribute the exponent to each factor within the parentheses. This gives us:

    72(a9)2(b5)27^2 \cdot (a^9)^2 \cdot (b^{-5})^2

  2. Simplify each part:

    • 72=497^2 = 49
    • (a9)2=a9×2=a18(a^9)^2 = a^{9 \times 2} = a^{18}
    • (b5)2=b5×2=b10(b^{-5})^2 = b^{-5 \times 2} = b^{-10}
  3. Combine the results: 49a18b1049a^{18}b^{-10}

  4. Eliminate negative exponents: To get rid of the negative exponent for bb, we move it to the denominator: 49a18b10\frac{49a^{18}}{b^{10}}

Final Simplified Expression:

49a18b10\frac{49a^{18}}{b^{10}}

If you need further clarification or have any questions, feel free to ask! Here are some related questions:

  1. What is the law of exponents used to simplify expressions like this one?
  2. How do negative exponents relate to fractions?
  3. Can the exponent rule also be applied to fractional exponents?
  4. What happens when you raise a product to a negative exponent?
  5. How do you handle variables with exponents when they appear in a fraction?

Tip: Always remember that negative exponents mean "take the reciprocal" of the base.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponents
Algebraic Expressions

Formulas

Exponent rule: (x^a)^b = x^(a*b)
Exponent rule: x^(-a) = 1/x^a

Theorems

-

Suitable Grade Level

Grades 8-10