Math Problem Statement

(2x - 3)^2 - (x + 1)^2

Solution

The given expression is:

(2x3)2(x+1)2(2x - 3)^2 - (x + 1)^2

Let's simplify this step by step.

Step 1: Expand each squared term.

(2x3)2=(2x3)(2x3)=4x26x6x+9=4x212x+9(2x - 3)^2 = (2x - 3)(2x - 3) = 4x^2 - 6x - 6x + 9 = 4x^2 - 12x + 9 (x+1)2=(x+1)(x+1)=x2+x+x+1=x2+2x+1(x + 1)^2 = (x + 1)(x + 1) = x^2 + x + x + 1 = x^2 + 2x + 1

Step 2: Subtract the second expanded term from the first.

(4x212x+9)(x2+2x+1)(4x^2 - 12x + 9) - (x^2 + 2x + 1)

Distribute the negative sign:

4x212x+9x22x14x^2 - 12x + 9 - x^2 - 2x - 1

Step 3: Combine like terms.

(4x2x2)+(12x2x)+(91)(4x^2 - x^2) + (-12x - 2x) + (9 - 1) =3x214x+8= 3x^2 - 14x + 8

Final Simplified Expression:

3x214x+83x^2 - 14x + 8

This is the simplified form of the given expression.

Would you like any further clarification?


Here are 5 related questions you might want to explore:

  1. How do you simplify more complex polynomial expressions?
  2. What is the difference of squares, and how does it apply here?
  3. How do you solve quadratic equations after simplification?
  4. What happens if you factor the final expression 3x214x+83x^2 - 14x + 8?
  5. Can this expression be applied to any real-world scenarios?

Tip: When dealing with squared binomials, expanding them carefully step by step helps avoid common mistakes!

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Expressions
Difference of Squares

Formulas

Square of a binomial: (a + b)^2 = a^2 + 2ab + b^2
Difference of squares: a^2 - b^2 = (a - b)(a + b)

Theorems

Difference of Squares Theorem

Suitable Grade Level

Grades 9-11