Let's simplify the expression:

$(-2e - 3f + 4)(-e)$

Distribute $-e$ to each term inside the parentheses:

$= (-2e)(-e) + (-3f)(-e) + (4)(-e)$

Now, simplify each term:

1. $(-2e)(-e) = 2e^2$
2. $(-3f)(-e) = 3ef$
3. $(4)(-e) = -4e$

Putting it all together:

$= 2e^2 + 3ef - 4e$

So the simplified expression is:

$2e^2 + 3ef - 4e$

Would you like further clarification or any additional details?

Here are five related questions:

1. How do you factor expressions like $2e^2 + 3ef - 4e$?
2. What happens if you factor out a common term in the expression $2e^2 + 3ef - 4e$?
3. How do you expand binomials in algebra, especially with multiple variables like in the given problem?
4. Can you solve for $e$ or $f$ in an equation derived from this expression?
5. What other operations can you apply to the expression, such as combining like terms?

Tip: When distributing in algebra, always multiply each term in the first parenthesis by each term in the second to ensure you don't miss any parts of the expansion.