The expression you've provided is $2^{3x} - 2^{-3x}$.

This is an exponential expression involving powers of 2, where the exponents depend on $x$.

Step-by-step breakdown:

• $2^{3x}$ means $2$ raised to the power of $3x$.
• $2^{-3x}$ means $2$ raised to the power of $-3x$, which can also be written as $\frac{1}{2^{3x}}$.

So, the expression is:

$2^{3x} - \frac{1}{2^{3x}}$

This expression is already in a simplified form, but if you want to explore further or have a specific value of $x$, you can substitute that value to evaluate the expression.

Would you like to solve it for a specific value of $x$, or do you need further clarification on how to approach this?

Here are 5 related questions:

1. What happens if you set $x = 1$?
2. How do you simplify expressions with both positive and negative exponents?
3. Can this expression be written in terms of a hyperbolic sine function?
4. What is the derivative of $2^{3x} - 2^{-3x}$ with respect to $x$?
5. How can you graph the expression $2^{3x} - 2^{-3x}$?

Tip:

When dealing with negative exponents, remember that $a^{-n} = \frac{1}{a^n}$.