Math Problem Statement

answer question

Simplify each expression and write the result in the form a + bi.

Solution

Let's go through each expression and simplify it in the form a+bia + bi, where aa is the real part and bb is the imaginary part.


Part a: 4+494 + \sqrt{49}

  • The square root of 49 is 7, so: 4+49=4+7=114 + \sqrt{49} = 4 + 7 = 11
  • This is a real number, so the result is 11+0i11 + 0i.

Part b: 38i7\frac{3 - 8i}{7}

  • Distribute the division by 7: 378i7\frac{3}{7} - \frac{8i}{7}
  • The real part is 37\frac{3}{7}, and the imaginary part is 87-\frac{8}{7}, so the result is: 3787i\frac{3}{7} - \frac{8}{7}i

Part c: 10+7520\frac{10 + \sqrt{-75}}{20}

  • First, simplify 75\sqrt{-75}: 75=175=i253=i53=5i3\sqrt{-75} = \sqrt{-1} \cdot \sqrt{75} = i \cdot \sqrt{25 \cdot 3} = i \cdot 5\sqrt{3} = 5i\sqrt{3}
  • Now substitute into the expression: 10+5i320\frac{10 + 5i\sqrt{3}}{20}
  • Simplify by dividing both terms by 20: 1020+5i320=12+i34\frac{10}{20} + \frac{5i\sqrt{3}}{20} = \frac{1}{2} + \frac{i\sqrt{3}}{4}
  • The result is: 12+i34\frac{1}{2} + \frac{i\sqrt{3}}{4}

Summary of results:

  1. 11+0i11 + 0i
  2. 3787i\frac{3}{7} - \frac{8}{7}i
  3. 12+i34\frac{1}{2} + \frac{i\sqrt{3}}{4}

Let me know if you'd like further details on any of these steps!

Follow-up Questions:

  1. What are the properties of complex numbers in polar form?
  2. How can we find the modulus of a complex number?
  3. Can you explain how to multiply complex numbers?
  4. How do we handle complex numbers with higher roots (e.g., cube roots)?
  5. How does Euler’s formula relate to complex numbers?

Tip:

When simplifying square roots of negative numbers, always factor out 1=i\sqrt{-1} = i, which converts the problem into handling imaginary numbers!

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Square Roots
Imaginary Numbers

Formulas

√(-1) = i
Distributing fractions in complex numbers
Simplifying square roots

Theorems

Basic properties of imaginary numbers
Complex number addition and division

Suitable Grade Level

Grades 9-11