Math Problem Statement

(6-7i)/(3i)

Solution

To simplify the expression 67i3i\frac{6 - 7i}{3i}, we follow a systematic process:

Step 1: Multiply both the numerator and the denominator by the complex conjugate of the denominator, which in this case is ii (since the denominator is 3i3i).

67i3i×ii=(67i)i(3i)i\frac{6 - 7i}{3i} \times \frac{i}{i} = \frac{(6 - 7i) \cdot i}{(3i) \cdot i}

Step 2: Simplify the denominator:

(3i)i=3i2=3(1)=3(3i) \cdot i = 3i^2 = 3(-1) = -3

Step 3: Distribute ii in the numerator:

(67i)i=6i7i2(6 - 7i) \cdot i = 6i - 7i^2 Since i2=1i^2 = -1, we have:

6i7(1)=6i+76i - 7(-1) = 6i + 7

Step 4: Rewrite the fraction:

6i+73\frac{6i + 7}{-3}

Step 5: Split the fraction:

6i3+73=2i73\frac{6i}{-3} + \frac{7}{-3} = -2i - \frac{7}{3}

Thus, the simplified result is:

732i-\frac{7}{3} - 2i

Final Answer:

732i\boxed{-\frac{7}{3} - 2i}

Would you like further details or have any questions on this process?

Here are 5 related questions you might find interesting:

  1. What is the conjugate of a complex number and why is it useful in simplifying expressions?
  2. How do we handle division of complex numbers involving real and imaginary parts?
  3. What does the notation ii represent in complex numbers?
  4. Can you explain the process of multiplying complex numbers and distributing terms?
  5. How do you simplify expressions involving i2i^2?

Tip: When dividing complex numbers, always multiply both the numerator and denominator by the conjugate of the denominator to eliminate complex numbers in the denominator.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Complex Numbers
Algebra
Division of Complex Numbers

Formulas

Multiplying by the complex conjugate
i^2 = -1

Theorems

Complex conjugate theorem

Suitable Grade Level

Grades 9-12