Math Problem Statement

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Simplify the following algebraic fractions: 1. (12a)/3 2. (14ab^2)/(2b) 3. (20b)/(5b) 4. (50b^2c^2)/(5bc) 5. (35c^2)/(7c) 6. (80ab^2c^3)/(8b^2c^2)

Solution

I have examined the image. Let's work through the simplifications step by step for each fraction:

  1. 12a3\frac{12a}{3}: Simplify the coefficients:
    12a3=4a\frac{12a}{3} = 4a

  2. 14ab22b\frac{14ab^2}{2b}: Simplify the coefficients and cancel common factors of bb: 14ab22b=142ab2b=7ab\frac{14ab^2}{2b} = \frac{14}{2} \cdot a \cdot \frac{b^2}{b} = 7ab

  3. 20b5b\frac{20b}{5b}: The bb's cancel out, and simplify the coefficients: 20b5b=4\frac{20b}{5b} = 4

  4. 50b2c25bc\frac{50b^2c^2}{5bc}: Simplify the coefficients and cancel common factors of bb and cc: 50b2c25bc=505b2bc2c=10bc\frac{50b^2c^2}{5bc} = \frac{50}{5} \cdot \frac{b^2}{b} \cdot \frac{c^2}{c} = 10bc

  5. 35c27c\frac{35c^2}{7c}: Simplify the coefficients and cancel a factor of cc: 35c27c=5c\frac{35c^2}{7c} = 5c

  6. 80ab2c38b2c2\frac{80ab^2c^3}{8b^2c^2}: Simplify the coefficients and cancel common factors of bb and cc: 80ab2c38b2c2=808b2b2c3c2=10ac\frac{80ab^2c^3}{8b^2c^2} = \frac{80}{8} \cdot \frac{b^2}{b^2} \cdot \frac{c^3}{c^2} = 10ac

Let me know if you'd like further details or have any questions.

Related questions:

  1. How can you simplify complex algebraic fractions more efficiently?
  2. What is the importance of canceling common factors in algebra?
  3. Can this method be applied to more complex polynomials?
  4. What are the properties of exponents used in simplification?
  5. How do you handle negative exponents in fraction simplification?

Tip: Always cancel out common factors carefully to avoid errors in simplification.

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Math Problem Analysis

Mathematical Concepts

Algebra
Fraction Simplification
Variables and Exponents
Factoring

Formulas

Simplification of fractions: (a * b)/(c * d) = (a/c) * (b/d)
Exponent rules: a^m / a^n = a^(m-n)

Theorems

Laws of Exponents
Factorization
Simplifying Rational Expressions

Suitable Grade Level

Grades 7-9