Math Problem Statement

1+cos2theta

Solution

The expression 1+cos(2θ)1 + \cos(2\theta) can be simplified using trigonometric identities. One common approach is to use the double-angle identity for cosine:

cos(2θ)=2cos2(θ)1\cos(2\theta) = 2\cos^2(\theta) - 1

Substitute this identity into 1+cos(2θ)1 + \cos(2\theta):

1+cos(2θ)=1+(2cos2(θ)1)1 + \cos(2\theta) = 1 + (2\cos^2(\theta) - 1)

Simplifying further:

1+cos(2θ)=2cos2(θ)1 + \cos(2\theta) = 2\cos^2(\theta)

Thus:

1+cos(2θ)=2cos2(θ)1 + \cos(2\theta) = 2\cos^2(\theta)

Alternatively, we can use the identity cos(2θ)=12sin2(θ)\cos(2\theta) = 1 - 2\sin^2(\theta) and rewrite the expression in terms of sin(θ)\sin(\theta):

1+cos(2θ)=1+(12sin2(θ))1 + \cos(2\theta) = 1 + (1 - 2\sin^2(\theta))

Simplify:

1+cos(2θ)=22sin2(θ)=2cos2(θ)1 + \cos(2\theta) = 2 - 2\sin^2(\theta) = 2\cos^2(\theta)

Would you like more details, or do you have any questions?

Here are some related questions you might find helpful:

  1. How does cos(2θ)\cos(2\theta) relate to other trigonometric identities?
  2. How can we derive the double-angle identities for sine and cosine?
  3. What other forms can 1+cos(2θ)1 + \cos(2\theta) take using different trigonometric identities?
  4. Can we simplify 1+cos2(θ)1 + \cos^2(\theta) using similar methods?
  5. How can 1+cos(2θ)1 + \cos(2\theta) be applied in integration?

Tip: Recognizing key trigonometric identities, like the double-angle formulas, can simplify complex expressions and are especially useful in calculus and physics applications.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Double-Angle Identities
Cosine Function

Formulas

cos(2θ) = 2cos²(θ) - 1
cos(2θ) = 1 - 2sin²(θ)

Theorems

Double-Angle Identity for Cosine

Suitable Grade Level

Grades 10-12