Math Problem Statement

(sec^2A-6tanA+7)/sec^2A-5

Solution

To simplify the expression sec2A6tanA+7sec2A5\frac{\sec^2A - 6\tan A + 7}{\sec^2A} - 5, follow these steps:

Step 1: Separate the Fraction

The expression can be rewritten as: sec2Asec2A6tanAsec2A+7sec2A5\frac{\sec^2A}{\sec^2A} - \frac{6\tan A}{\sec^2A} + \frac{7}{\sec^2A} - 5

Step 2: Simplify Each Term

  • The first term simplifies to 11 since sec2Asec2A=1\frac{\sec^2A}{\sec^2A} = 1.
  • The second term can be simplified by recognizing that sec2A=1+tan2A\sec^2A = 1 + \tan^2A. Thus, 6tanAsec2A=6tanA1+tan2A\frac{6\tan A}{\sec^2A} = \frac{6\tan A}{1 + \tan^2A}
  • The third term simplifies to 7sec2A=7cos2A\frac{7}{\sec^2A} = 7\cos^2A since sec2A=1cos2A\sec^2A = \frac{1}{\cos^2A}.

Step 3: Combine and Simplify the Expression

So, the expression becomes: 16tanA1+tan2A+7cos2A51 - \frac{6\tan A}{1 + \tan^2A} + 7\cos^2A - 5

Finally, simplify further: =(15)+7cos2A6tanA1+tan2A= (1 - 5) + 7\cos^2A - \frac{6\tan A}{1 + \tan^2A} =4+7cos2A6tanA1+tan2A= -4 + 7\cos^2A - \frac{6\tan A}{1 + \tan^2A}

Final Simplified Expression:

4+7cos2A6tanA1+tan2A\boxed{-4 + 7\cos^2A - \frac{6\tan A}{1 + \tan^2A}}

Would you like more details on any part of this simplification? Here are some related questions:

  1. How do you simplify trigonometric identities?
  2. What is the relationship between sec2A\sec^2A and tan2A\tan^2A?
  3. Can you explain how to simplify expressions involving secA\sec A and tanA\tan A?
  4. How would this expression change if you were given a specific value for AA?
  5. What are some common tricks to simplifying complex trigonometric expressions?

Tip: Always check if a trigonometric identity can simplify the expression before performing algebraic operations.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Trigonometric Identities
Simplification of Expressions

Formulas

Trigonometric identities involving secant, tangent, and cosine

Theorems

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Suitable Grade Level

Grades 10-12