Math Problem Statement

Simplify \(\sqrt{81} + 5\sqrt{27}\).

Solution

Let's solve the problem step by step.

The expression to simplify is:

81+527\sqrt{81} + 5\sqrt{27}

Step 1: Simplify the square roots

  • 81=9\sqrt{81} = 9, because 92=819^2 = 81.
  • For 5275\sqrt{27}, notice that 27=9327 = 9 \cdot 3, so: 27=93=93=33.\sqrt{27} = \sqrt{9 \cdot 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}. Thus: 527=533=153.5\sqrt{27} = 5 \cdot 3\sqrt{3} = 15\sqrt{3}.

Step 2: Combine terms

The simplified expression becomes: 81+527=9+153.\sqrt{81} + 5\sqrt{27} = 9 + 15\sqrt{3}.

Final Answer:

9+1539 + 15\sqrt{3}

Would you like further clarification or details about this process? Let me know!


Here are 5 related questions for further practice:

  1. Simplify 64+332\sqrt{64} + 3\sqrt{32}.
  2. Simplify 2503182\sqrt{50} - 3\sqrt{18}.
  3. Expand and simplify (2+3)(33)(2 + \sqrt{3})(3 - \sqrt{3}).
  4. Combine and simplify 427+2124\sqrt{27} + 2\sqrt{12}.
  5. Rationalize the denominator of 53\frac{5}{\sqrt{3}}.

Tip: When simplifying square roots, always look for perfect square factors to simplify them systematically.

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Math Problem Analysis

Mathematical Concepts

Simplification of square roots
Radicals
Basic algebra

Formulas

Simplification of square roots \(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\)
Product of a constant and a square root \(k \cdot \sqrt{a}\)

Theorems

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Suitable Grade Level

Grades 7-9