To simplify the square root of 32, we'll start by factoring 32 into its prime factors:

$32 = 2 \times 2 \times 2 \times 2 \times 2 = 2^5$

Now, we can express the square root of 32 as:

$\sqrt{32} = \sqrt{2^5}$

We know that:

$\sqrt{2^5} = \sqrt{2^4 \times 2} = \sqrt{2^4} \times \sqrt{2} = 2^2 \times \sqrt{2} = 4\sqrt{2}$

Thus, the simplest radical form of $\sqrt{32}$ is:

$\boxed{4\sqrt{2}}$

Would you like more details or have any questions? Here are some related questions you might find interesting:

1. How do you simplify $\sqrt{50}$?
2. What is the simplest radical form of $\sqrt{72}$?
3. How do you simplify $\sqrt{18}$?
4. What is the simplest radical form of $\sqrt{128}$?
5. How do you simplify $\sqrt{80}$?

Tip: When simplifying square roots, look for the largest perfect square factor of the number under the radical.