To simplify $\sqrt{180}$, follow these steps:

First, factorize 180 into its prime factors: $180 = 2^2 \times 3^2 \times 5$

Now, apply the square root: $\sqrt{180} = \sqrt{2^2 \times 3^2 \times 5}$ $\sqrt{180} = \sqrt{(2 \times 3)^2 \times 5} = 2 \times 3 \times \sqrt{5} = 6\sqrt{5}$

So, the simplified form of $\sqrt{180}$ is: $\sqrt{180} = 6\sqrt{5}$

Would you like more details, or do you have any questions?

Here are 5 related questions:

1. How do you simplify $\sqrt{75}$?
2. What is the square root of $\sqrt{360}$?
3. How do you find the square root of a product like $12 \times 15$?
4. What is the simplest form of $\sqrt{45}$?
5. How do you simplify $\sqrt{72}$ and compare it with $\sqrt{180}$?

Tip: When simplifying square roots, look for pairs of prime factors, as these will simplify neatly.