Math Problem Statement

Fully simplify the expression below and write your answer as a single fraction. start fraction, x, to the power 5 , plus, 9, x, to the power 4 , minus, 10, x, cubed, divided by, 9, x, left parenthesis, x, minus, 1, right parenthesis, squared, end fraction, dot, start fraction, 6, x, squared, minus, 36, x, minus, 240, divided by, x, squared, minus, 100, end fraction 9x(x−1) 2

x 5 +9x 4 −10x 3

​ ⋅ x 2 −100 6x 2 −36x−240 ​

Solution

To simplify the given expression, we'll break it down step by step.

Expression:

x5+9x410x39x(x1)26x236x240x2100\frac{x^5 + 9x^4 - 10x^3}{9x(x - 1)^2} \cdot \frac{6x^2 - 36x - 240}{x^2 - 100}

Step 1: Factorize where possible

  1. Factorize the numerator of the first fraction:

    • x5+9x410x3x^5 + 9x^4 - 10x^3 can be factored by taking out the common factor x3x^3: x5+9x410x3=x3(x2+9x10)x^5 + 9x^4 - 10x^3 = x^3(x^2 + 9x - 10)
    • Now, we can factor x2+9x10x^2 + 9x - 10 further by finding factors of 10-10 that add up to 99: x2+9x10=(x+10)(x1)x^2 + 9x - 10 = (x + 10)(x - 1)
    • Thus, the numerator becomes: x3(x+10)(x1)x^3(x + 10)(x - 1)
  2. Factorize the denominator of the second fraction:

    • x2100x^2 - 100 is a difference of squares: x2100=(x+10)(x10)x^2 - 100 = (x + 10)(x - 10)
  3. Factorize the numerator of the second fraction:

    • 6x236x2406x^2 - 36x - 240 can be factored by taking out the common factor 6: 6x236x240=6(x26x40)6x^2 - 36x - 240 = 6(x^2 - 6x - 40)
    • Then factor x26x40x^2 - 6x - 40 by finding factors of 40-40 that add up to 6-6: x26x40=(x10)(x+4)x^2 - 6x - 40 = (x - 10)(x + 4)
    • Thus, the numerator becomes: 6(x10)(x+4)6(x - 10)(x + 4)

Step 2: Substitute factorizations into the expression

x3(x+10)(x1)9x(x1)26(x10)(x+4)(x+10)(x10)\frac{x^3(x + 10)(x - 1)}{9x(x - 1)^2} \cdot \frac{6(x - 10)(x + 4)}{(x + 10)(x - 10)}

Step 3: Simplify the expression

  1. Cancel out common factors:
    • xx cancels with xx in the denominator.
    • x+10x + 10 cancels with x+10x + 10.
    • x1x - 1 cancels one of the x1x - 1 in the denominator.
    • x10x - 10 cancels with x10x - 10.

This leaves us with: x26(x+4)9(x1)\frac{x^2 \cdot 6(x + 4)}{9(x - 1)}

  1. Simplify the remaining expression:
    • Distribute the 66 in the numerator: 6x2(x+4)=6x3+24x26x^2(x + 4) = 6x^3 + 24x^2

Final simplified expression: 6x3+24x29(x1)\frac{6x^3 + 24x^2}{9(x - 1)}

  1. Further simplification (if possible):
    • Factor out the common factor 33 from the numerator: 6x3+24x29(x1)=3(2x3+8x2)9(x1)=2x3+8x23(x1)\frac{6x^3 + 24x^2}{9(x - 1)} = \frac{3(2x^3 + 8x^2)}{9(x - 1)} = \frac{2x^3 + 8x^2}{3(x - 1)}

Thus, the fully simplified expression is: 2x3+8x23(x1)\boxed{\frac{2x^3 + 8x^2}{3(x - 1)}}

Would you like details on any specific step, or have any further questions?


Relative Questions:

  1. How do you factor polynomials like x2+9x10x^2 + 9x - 10?
  2. What are the rules for simplifying expressions with exponents?
  3. Can you explain the difference of squares formula?
  4. How do you handle fractions with polynomial expressions in the numerator and denominator?
  5. How do you determine if further simplification is possible?

Tip: Always look for common factors in both the numerator and denominator to simplify expressions effectively.

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Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Factorization
Simplification of Rational Expressions
Difference of Squares

Formulas

Difference of squares: a^2 - b^2 = (a - b)(a + b)
Factoring quadratic expressions: ax^2 + bx + c
Simplifying rational expressions by canceling common factors

Theorems

Factor Theorem
Difference of Squares Theorem
Polynomial Division

Suitable Grade Level

Grades 9-12