The expression you provided is $\ln\left(e^{1/3}\right)$.

Using the property of logarithms, $\ln(a^b) = b \cdot \ln(a)$, we can simplify this expression.

$\ln\left(e^{1/3}\right) = \frac{1}{3} \cdot \ln(e)$

Since $\ln(e) = 1$, the expression simplifies to:

$\frac{1}{3} \times 1 = \frac{1}{3}$

So, $\ln\left(e^{1/3}\right) = \frac{1}{3}$.

Would you like more details on logarithmic properties or have any other questions?

Here are 5 related questions:

1. How would you simplify $\ln\left(e^2\right)$?
2. What is the value of $\ln(e^x)$ for any real number $x$?
3. How can you use logarithm properties to solve $\ln\left(a^b\right)$?
4. What is the derivative of $\ln\left(e^x\right)$ with respect to $x$?
5. How does the natural logarithm function behave as $x$ approaches infinity?

Tip: The natural logarithm $\ln(x)$ is the inverse function of the exponential function $e^x$.