Math Problem Statement

Simplify the expression \( \frac{4x^{-1} - (5y)^{-1}}{x^{-2}} \).

Solution

from PIL import Image import pytesseract

Load the uploaded image

image_path = "/mnt/data/1731998136182gt955fqg.jpg" image = Image.open(image_path)

Use pytesseract to extract the mathematical content from the image

extracted_text = pytesseract.image_to_string(image, config='--psm 6') extracted_text"4x‘ - (Gy) '\nge 5 ‘a\n""4x‘ - (Gy) '\nge 5 ‘a\n"successThe extracted mathematical expression is unclear, but it seems to resemble:

4x1(5y)1x2=?\frac{4x^{-1} - (5y)^{-1}}{x^{-2}} = \, ?

I will interpret and solve it accordingly. Let's simplify the given expression step by step:

Expression:

4x1(5y)1x2\frac{4x^{-1} - (5y)^{-1}}{x^{-2}}

Step-by-step simplification:

  1. Rewrite the terms with positive exponents:

    • 4x1=4x4x^{-1} = \frac{4}{x}
    • (5y)1=15y(5y)^{-1} = \frac{1}{5y}
    • x2=1x2x^{-2} = \frac{1}{x^2}

    Substituting these into the expression gives: 4x15y1x2\frac{\frac{4}{x} - \frac{1}{5y}}{\frac{1}{x^2}}

  2. Multiply the numerator by the reciprocal of the denominator: (4x15y)×x2\left(\frac{4}{x} - \frac{1}{5y}\right) \times x^2

  3. Expand and simplify: 4xx2=4x\frac{4}{x} \cdot x^2 = 4x 15yx2=x25y\frac{1}{5y} \cdot x^2 = \frac{x^2}{5y}

    So the expression becomes: 4xx25y4x - \frac{x^2}{5y}

  4. Combine into a single fraction: 20xyx25y\frac{20xy - x^2}{5y}

Final Answer:

20xyx25y\frac{20xy - x^2}{5y}

Would you like further explanation or a deeper breakdown of any steps?


Related Questions:

  1. How do negative exponents work in general?
  2. Can this expression be simplified further for specific values of xx and yy?
  3. What happens if y=0y = 0 in this expression?
  4. How would this change if the powers in the numerator were positive?
  5. Can you derive the same result using a different algebraic method?

Tip:

When simplifying algebraic fractions, always aim to rewrite negative exponents as positive for better clarity.

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Math Problem Analysis

Mathematical Concepts

Algebra
Negative Exponents
Fractional Expressions

Formulas

Negative exponent rule: \( a^{-n} = \frac{1}{a^n} \)
Fraction simplification: \( \frac{a}{\frac{b}{c}} = a \times \frac{c}{b} \)

Theorems

Exponentiation Rules

Suitable Grade Level

Grades 9-11