Math Problem Statement

Simplify the mathematical expression: \(\frac{\left( -3^2 \right)^3 \cdot 27}{9^4 \cdot \left( \frac{1}{3} \right)}\).

Solution

Let’s analyze and solve the given expression step by step. Here's the equation extracted from the image:

(32)32794(13).\frac{\left( -3^2 \right)^3 \cdot 27}{9^4 \cdot \left( \frac{1}{3} \right)}.


Step 1: Simplify individual components

1. Simplify (32)3(-3^2)^3:

  • First, calculate 32-3^2: 32=(3)(3)=9.-3^2 = (-3) \cdot (-3) = 9.
  • Now, cube this result: (9)3=999=729.(9)^3 = 9 \cdot 9 \cdot 9 = 729. Thus, (32)3=729(-3^2)^3 = 729.

2. Simplify 271/327^{1/3}:

The cube root of 2727 is: 271/3=3.27^{1/3} = 3.

3. Simplify 949^4:

94=(32)4=38.9^4 = (3^2)^4 = 3^{8}.

4. Simplify the denominator with (13)\left( \frac{1}{3} \right):

When multiplying, 13\frac{1}{3} remains as is.


Step 2: Rewrite the expression

Substitute the simplified components back into the equation: 72933813.\frac{729 \cdot 3}{3^8 \cdot \frac{1}{3}}.


Step 3: Combine terms

Simplify the numerator:

7293=2187.729 \cdot 3 = 2187.

Simplify the denominator:

3813=381=37.3^8 \cdot \frac{1}{3} = 3^{8-1} = 3^7.

The expression is now: 218737.\frac{2187}{3^7}.


Step 4: Simplify the fraction

Since 2187=372187 = 3^7, the fraction simplifies to: 3737=1.\frac{3^7}{3^7} = 1.


Final Answer:

1\boxed{1}

Would you like a detailed breakdown of any particular step?


Related Questions:

  1. How is the cube root of a number calculated?
  2. Why does 949^4 become 383^8 when expressed with exponents of prime factors?
  3. What are the steps to simplify expressions with negative bases and exponents?
  4. How can we handle expressions involving fractions like 13\frac{1}{3} more easily?
  5. Why does 37÷373^7 \div 3^7 simplify to 1?

Tip:

When working with exponents, always express terms with the same base whenever possible—it simplifies calculations significantly!

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Math Problem Analysis

Mathematical Concepts

Simplification of expressions
Exponents and powers
Fractions and reciprocal operations
Cube roots and powers

Formulas

Base exponent property: \((a^m)^n = a^{m \cdot n}\)
Fraction simplification: \(\frac{a}{b} \cdot c = \frac{a \cdot c}{b}\)
Prime factorization for powers: \(n^m = (a^b)^m = a^{b \cdot m}\)

Theorems

Exponent rules: \(a^m \cdot a^n = a^{m+n}\)
Simplification of powers: \(\frac{a^m}{a^n} = a^{m-n}\)

Suitable Grade Level

Grades 9-12