Let's solve the expression \( 5(a + 3b) \) given that \( a = 4 \) and \( b = -3 \).

### Step 1: Substitute the values of \( a \) and \( b \) into the expression.
\[
5(a + 3b) = 5(4 + 3(-3))
\]

### Step 2: Simplify inside the parentheses.
\[
4 + 3(-3) = 4 - 9 = -5
\]

### Step 3: Multiply by 5.
\[
5(-5) = -25
\]

Thus, the value of the expression is \( -25 \).

Would you like further explanation or any additional details?

Here are five related questions:
1. How would the expression change if \( b = 3 \) instead of \( -3 \)?
2. What happens if you use a different constant outside the parentheses, like \( 7(a + 3b) \)?
3. How would you expand the expression \( 5(a + 3b) \) before substituting the values of \( a \) and \( b \)?
4. Can you solve a similar expression \( 4(a - 2b) \) with the same values for \( a \) and \( b \)?
5. What is the result if \( b = 0 \), keeping \( a = 4 \) in the expression \( 5(a + 3b) \)?

**Tip:** When simplifying expressions, always handle operations inside parentheses first.

Learn how to simplify the algebraic expression 5(a + 3b) with given values a = 4 and b = -3. Follow a detailed step-by-step solution using the distributive property. This problem is suitable for students in Grades 6-8.

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