Math Problem Statement

5(a+3b) a=4 b=-3

Solution

Let's solve the expression 5(a+3b)5(a + 3b) given that a=4a = 4 and b=3b = -3.

Step 1: Substitute the values of aa and bb into the expression.

5(a+3b)=5(4+3(3))5(a + 3b) = 5(4 + 3(-3))

Step 2: Simplify inside the parentheses.

4+3(3)=49=54 + 3(-3) = 4 - 9 = -5

Step 3: Multiply by 5.

5(5)=255(-5) = -25

Thus, the value of the expression is 25-25.

Would you like further explanation or any additional details?

Here are five related questions:

  1. How would the expression change if b=3b = 3 instead of 3-3?
  2. What happens if you use a different constant outside the parentheses, like 7(a+3b)7(a + 3b)?
  3. How would you expand the expression 5(a+3b)5(a + 3b) before substituting the values of aa and bb?
  4. Can you solve a similar expression 4(a2b)4(a - 2b) with the same values for aa and bb?
  5. What is the result if b=0b = 0, keeping a=4a = 4 in the expression 5(a+3b)5(a + 3b)?

Tip: When simplifying expressions, always handle operations inside parentheses first.

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Math Problem Analysis

Mathematical Concepts

Algebra
Simplification of Expressions

Formulas

Distributive Property: a(b + c) = ab + ac

Theorems

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Suitable Grade Level

Grades 6-8