Math Problem Statement

Simplify to an expression involving a single trigonometric function with no fractions: cos(-x) + (sin(-x) / cot(-x))

Solution

We are tasked with simplifying the following trigonometric expression:

cos(x)+sin(x)cot(x)\cos(-x) + \frac{\sin(-x)}{\cot(-x)}

Let us proceed step by step:


Step 1: Apply trigonometric identities for negative angles

  1. Cosine: cos(x)=cos(x)\cos(-x) = \cos(x) because cosine is an even function.
  2. Sine: sin(x)=sin(x)\sin(-x) = -\sin(x) because sine is an odd function.
  3. Cotangent: cot(x)=cot(x)\cot(-x) = -\cot(x) because cotangent is the ratio of cosine and sine (cot(x)=cos(x)sin(x)\cot(x) = \frac{\cos(x)}{\sin(x)}).

Substitute these into the expression:

cos(x)+sin(x)cot(x)=cos(x)+sin(x)cot(x).\cos(-x) + \frac{\sin(-x)}{\cot(-x)} = \cos(x) + \frac{-\sin(x)}{-\cot(x)}.


Step 2: Simplify the fraction

Notice that the negatives in the numerator and denominator cancel out:

sin(x)cot(x)=sin(x)cot(x).\frac{-\sin(x)}{-\cot(x)} = \frac{\sin(x)}{\cot(x)}.

Now the expression becomes:

cos(x)+sin(x)cot(x).\cos(x) + \frac{\sin(x)}{\cot(x)}.


Step 3: Replace cot(x)\cot(x) with its definition

The cotangent function is defined as:

cot(x)=cos(x)sin(x).\cot(x) = \frac{\cos(x)}{\sin(x)}.

Substitute this into the fraction:

sin(x)cot(x)=sin(x)cos(x)sin(x).\frac{\sin(x)}{\cot(x)} = \frac{\sin(x)}{\frac{\cos(x)}{\sin(x)}}.

Simplify the complex fraction by multiplying by the reciprocal:

sin(x)cos(x)sin(x)=sin(x)sin(x)cos(x)=sin2(x)cos(x).\frac{\sin(x)}{\frac{\cos(x)}{\sin(x)}} = \sin(x) \cdot \frac{\sin(x)}{\cos(x)} = \frac{\sin^2(x)}{\cos(x)}.


Step 4: Combine terms over a common denominator

Now the expression is:

cos(x)+sin2(x)cos(x).\cos(x) + \frac{\sin^2(x)}{\cos(x)}.

To add these terms, write cos(x)\cos(x) with a common denominator:

cos(x)=cos2(x)cos(x).\cos(x) = \frac{\cos^2(x)}{\cos(x)}.

Thus:

cos(x)+sin2(x)cos(x)=cos2(x)cos(x)+sin2(x)cos(x).\cos(x) + \frac{\sin^2(x)}{\cos(x)} = \frac{\cos^2(x)}{\cos(x)} + \frac{\sin^2(x)}{\cos(x)}.

Combine the numerators:

cos2(x)+sin2(x)cos(x).\frac{\cos^2(x) + \sin^2(x)}{\cos(x)}.


Step 5: Use the Pythagorean identity

The Pythagorean identity states:

cos2(x)+sin2(x)=1.\cos^2(x) + \sin^2(x) = 1.

Substitute this into the expression:

cos2(x)+sin2(x)cos(x)=1cos(x).\frac{\cos^2(x) + \sin^2(x)}{\cos(x)} = \frac{1}{\cos(x)}.


Step 6: Simplify to a single trigonometric function

The reciprocal of cosine is secant (sec(x)\sec(x)):

1cos(x)=sec(x).\frac{1}{\cos(x)} = \sec(x).


Final Answer:

The simplified expression is:

sec(x).\boxed{\sec(x)}.


Do you want me to explain any step further or provide more examples? Let me know! Here are five related questions for further practice:

  1. Simplify cos(x)+sin(x)\cos(-x) + \sin(-x) using trigonometric identities.
  2. Simplify tan(x)+cot(x)\tan(-x) + \cot(-x).
  3. Prove that sin2(x)+cos2(x)=1\sin^2(x) + \cos^2(x) = 1 using the unit circle definition.
  4. Simplify sin2(x)1cos(x)\frac{\sin^2(x)}{1 - \cos(x)}.
  5. Simplify 1cos(2x)sin(2x)\frac{1 - \cos(2x)}{\sin(2x)}.

Tip: Always check for symmetry and parity properties (even or odd functions) when simplifying trigonometric expressions.

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Math Problem Analysis

Mathematical Concepts

Trigonometric Identities
Even and Odd Functions
Reciprocal Trigonometric Functions
Pythagorean Identity

Formulas

cos(-x) = cos(x)
sin(-x) = -sin(x)
cot(-x) = -cot(x)
cot(x) = cos(x) / sin(x)
cos^2(x) + sin^2(x) = 1

Theorems

Pythagorean Identity
Trigonometric Function Properties

Suitable Grade Level

Grades 10-12