Math Problem Statement

Simplify the complex rational expression by the method of your choice. StartStartFraction StartFraction 3 Over a squared EndFraction minus StartFraction 1 Over ab EndFraction minus StartFraction 2 Over b squared EndFraction OverOver StartFraction 2 Over a squared EndFraction minus StartFraction 5 Over ab EndFraction plus StartFraction 3 Over b squared EndFraction EndEndFraction Question content area bottom Part 1 StartStartFraction StartFraction 3 Over a squared EndFraction minus StartFraction 1 Over ab EndFraction minus StartFraction 2 Over b squared EndFraction OverOver StartFraction 2 Over a squared EndFraction minus StartFraction 5 Over ab EndFraction plus StartFraction 3 Over b squared EndFraction EndEndFraction equals    negative StartFraction 2 a plus 3 b Over 3 a minus 2 b EndFraction

​(Simplify your answer. Type your answer in factored​ form.)

Solution

To simplify the given complex rational expression:

3a21ab2b22a25ab+3b2,\frac{\frac{3}{a^2} - \frac{1}{ab} - \frac{2}{b^2}}{\frac{2}{a^2} - \frac{5}{ab} + \frac{3}{b^2}},

we will first combine the fractions in the numerator and denominator by finding a common denominator for each.

Step 1: Simplify the Numerator

The common denominator for the terms in the numerator is a2b2a^2 b^2:

3a2=3b2a2b2,1ab=ba2b2,2b2=2a2a2b2.\frac{3}{a^2} = \frac{3b^2}{a^2 b^2}, \quad \frac{1}{ab} = \frac{b}{a^2 b^2}, \quad \frac{2}{b^2} = \frac{2a^2}{a^2 b^2}.

Combining these, the numerator becomes:

3b2b2a2a2b2.\frac{3b^2 - b - 2a^2}{a^2 b^2}.

Step 2: Simplify the Denominator

Similarly, the common denominator for the terms in the denominator is also a2b2a^2 b^2:

2a2=2b2a2b2,5ab=5ba2b2,3b2=3a2a2b2.\frac{2}{a^2} = \frac{2b^2}{a^2 b^2}, \quad \frac{5}{ab} = \frac{5b}{a^2 b^2}, \quad \frac{3}{b^2} = \frac{3a^2}{a^2 b^2}.

Combining these, the denominator becomes:

2b25b+3a2a2b2.\frac{2b^2 - 5b + 3a^2}{a^2 b^2}.

Step 3: Form the Complex Fraction

The original expression simplifies to:

3b2b2a2a2b22b25b+3a2a2b2=3b2b2a22b25b+3a2.\frac{\frac{3b^2 - b - 2a^2}{a^2 b^2}}{\frac{2b^2 - 5b + 3a^2}{a^2 b^2}} = \frac{3b^2 - b - 2a^2}{2b^2 - 5b + 3a^2}.

Step 4: Factor the Numerator and Denominator

Now, we factor both the numerator and the denominator:

  • Numerator: 3b2b2a23b^2 - b - 2a^2 factors as (2a2+b3b2)=(2a2+3bb)-(2a^2 + b - 3b^2) = -(2a^2+ 3b - b)

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Expressions
Factoring

Formulas

Combining fractions with a common denominator
Simplifying complex fractions
Factoring polynomials

Theorems

Factorization

Suitable Grade Level

Grades 10-12