Math Problem Statement

Simplify the expression: \(\frac{2\sqrt{v^2} + 5\sqrt{v} + 2}{\sqrt{v}(1 - \sqrt{v})} \Big/ \left( \frac{1}{\sqrt{v^2}} + \frac{2}{\sqrt{v}} \right)\)

Solution

The expression you provided in the image is as follows:

2v2+5v+2v(1v)/(1v2+2v)\frac{2\sqrt{v^2} + 5\sqrt{v} + 2}{\sqrt{v}(1 - \sqrt{v})} \Big/ \left( \frac{1}{\sqrt{v^2}} + \frac{2}{\sqrt{v}} \right)

To simplify this expression, let's break down the steps:

  1. Rewrite the terms with square roots:
    We can simplify v2\sqrt{v^2} as vv and 1v2\frac{1}{\sqrt{v^2}} as 1v\frac{1}{v}. Similarly, we rewrite v\sqrt{v} as is.

    So, the expression becomes: 2v+5v+2v(1v)/(1v+2v)\frac{2v + 5\sqrt{v} + 2}{\sqrt{v}(1 - \sqrt{v})} \Big/ \left( \frac{1}{v} + \frac{2}{\sqrt{v}} \right)

  2. Simplify the denominator of the fraction on the right:
    Combine the terms in 1v+2v\frac{1}{v} + \frac{2}{\sqrt{v}} over a common denominator: 1v+2v=1+2v1/2v\frac{1}{v} + \frac{2}{\sqrt{v}} = \frac{1 + 2v^{1/2}}{v}

    So, the entire expression now looks like this: 2v+5v+2v(1v)/1+2vv\frac{2v + 5\sqrt{v} + 2}{\sqrt{v}(1 - \sqrt{v})} \Big/ \frac{1 + 2\sqrt{v}}{v}

  3. Rewrite the complex fraction:
    Dividing by a fraction is the same as multiplying by its reciprocal. Thus: 2v+5v+2v(1v)×v1+2v\frac{2v + 5\sqrt{v} + 2}{\sqrt{v}(1 - \sqrt{v})} \times \frac{v}{1 + 2\sqrt{v}}

  4. Simplify by canceling terms if possible:
    Now, multiply the numerators and the denominators. However, further simplification would depend on whether we can factor terms like 2v+5v+22v + 5\sqrt{v} + 2, which doesn’t factor neatly over integers.

Would you like me to proceed with further steps or have any particular questions?


Related Questions:

  1. How do I factor expressions involving square roots?
  2. Can you show examples of simplifying complex fractions step-by-step?
  3. What are some techniques to handle nested fractions in algebra?
  4. Could you explain simplifying expressions with radical terms further?
  5. How do I multiply expressions with different square root terms?

Tip:

When simplifying complex fractions, try to rewrite them as a multiplication by the reciprocal—it often makes the simplification process much easier.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Radical Expressions
Simplifying Complex Fractions

Formulas

\(\sqrt{v^2} = v\)
Reciprocal of fractions: \( \frac{a}{b} \Big/ \frac{c}{d} = \frac{a \cdot d}{b \cdot c} \)

Theorems

-

Suitable Grade Level

Grades 9-12