The expression in the image appears to be:

$\bar{X}\bar{Y}Z + \bar{X}Y\bar{Z} + \bar{X}YZ + XY\bar{Z}$

This looks like a Boolean algebra expression, where the variables $X$, $Y$, and $Z$ are binary (0 or 1), and the bars represent the NOT operation (negation).

To simplify or solve this, we can group terms if possible using Boolean algebra rules, such as:

• $X + \bar{X} = 1$
• $X \cdot X = X$
• $X \cdot \bar{X} = 0$

Let's simplify step by step:

1. The first two terms are: $\bar{X}\bar{Y}Z + \bar{X}Y\bar{Z}$.

   • Factor $\bar{X}$: $\bar{X}( \bar{Y}Z + Y\bar{Z} )$
   • This is in the form of the XOR operation: $\bar{X}(Y \oplus Z)$.

2. The next two terms are: $\bar{X}YZ + XY\bar{Z}$.

   • Combine $\bar{X}YZ$ with $XY\bar{Z}$.

Now, the full expression becomes:

$\bar{X}(Y \oplus Z) + (Y \oplus Z)$

Since both terms contain $Y \oplus Z$, we can factor it:

$(Y \oplus Z)(\bar{X} + X)$

Using $\bar{X} + X = 1$, the expression simplifies to:

$Y \oplus Z$

This is the simplified Boolean expression, where $\oplus$ represents XOR.

Would you like further details on Boolean simplification, or do you have any other questions?

Related questions:

1. What is the XOR (exclusive OR) operation in Boolean algebra?
2. How do De Morgan's laws apply to Boolean expressions?
3. Can this expression be represented as a truth table?
4. What are some common Boolean simplification rules?
5. How do Karnaugh maps help in simplifying Boolean functions?

Tip:

When simplifying Boolean expressions, always look for common factors and apply basic identities like $X + \bar{X} = 1$ to reduce the terms quickly.